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Using the Wronskian in this Problem, verify that the given functions form a fundamental solution set for the given differential equation and find a general solution.

y4-y=0;{ex,e-x,cosx,sinx}

Short Answer

Expert verified

Thus, it is verified that the given functions form a fundamental solution set for the given differential equation, and the general solution isy=Aex+Be-x+Ccosx+Dsinx.

Step by step solution

01

Using the concept of Wronskian

The given function is ex,e-x,cosx,sinx.

Apply the concept of Wronskian,

Wf1,f2,,fn=f1xf2xfnxf1'xf2'xfn'xf1n-1xf2n-1xfnn-1x

Therefore, the Wronskian of the given function is given as;

Wex,e-x,cosx,sinx=exe-xcosxsinxex-e-x-sinxcosxexe-x-cosx-sinxex-e-xsinx-cosx

Solve the above equation,

Wex,e-x,cosx,sinx=exe-xcosxsinxex-e-x-sinxcosxexe-x-cosx-sinxex-e-xsinx-cosx=ex-e-x-sinxcosxe-x-cosx-sinx-e-xsinx-cosx-e-xex-sinxcosxex-cosx-sinxexsinx-cosx+cosxex-e-xcosxexe-x-sinxex-e-x-cosx-sinxex-e-x-sinxexe-x-cosxex-e-xsinx=ex-2e-x-e-x2ex+cosx-4exe-xcosx-sinx4exe-xsinx=-4exe-x-4exe-xcos2x-4exe-xsin2x=-4exe-x-4exe-xcos2x+sin2x=-8exe-x

02

Step 2:Find a general solution

The Wronskian of the above functionis never zero on the interval a,b.

Thus, it isverified that the given functions form a fundamental solution set for the given differential equation.

Therefore, the general solution isy=Aex+Be-x+Ccosx+Dsinx.

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Most popular questions from this chapter

use the annihilator method to determinethe form of a particular solution for the given equation.

y''+2y'+2y=e-xcosx+x2

In Problems 1-6, use the method of variation of parameters to determine a particular solution to the given equation.y'''+y'=secθtanθ,0<θ<π/2

use the annihilator method to determinethe form of a particular solution for the given equation.

y'''+2y''-y'-2y=ex-1

Deflection of a Beam Under Axial Force. A uniform beam under a load and subject to a constant axial force is governed by the differential equation

y(4)(x)-k2y''(x)=q(x),0<x<L,

where is the deflection of the beam, L is the length of the beam, k2is proportional to the axial force, and q(x) is proportional to the load (see Figure 6.2).

(a) Show that a general solution can be written in the form

y(x)=C1+C2x+C3ekx+C4e-kx+1k2q(x)xdx-xk2q(x)dx+ekx2k3q(x)e-kxdx-e-kx2k3q(x)ekxdx

(b) Show that the general solution in part (a) can be rewritten in the form

y(x)=c1+c2x+c3ekx+c4e-kx+0xq(s)G(s,x)ds,

where

G(s,x):=s-xk2-sinh[k(s-x)]k3.

(c) Let q(x)=1 First compute the general solution using the formula in part (a) and then using the formula in part (b). Compare these two general solutions with the general solution

y(x)=B1+B2x+B3ekx+B4e-kx-12k2x2,

which one would obtain using the method of undetermined coefficients.

Find a general solution toy(4)+2y(3)+4y''+3y'+2y=0 by using Newton’s method to approximate numerically the roots of the auxiliary equation. [Hint: To find complex roots, use the Newton recursion formulazn+1=znf(zn)f'(zn)and start with a complex initial guess z0.]

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