Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

A sailboat has been running (on a straight course) under a light wind at 1 m/sec. Suddenly the wind picks up, blowing hard enough to apply a constant force of 600 N to the sailboat. The only other force acting on the boat is water resistance that is proportional to the velocity of the boat. If the proportionality constant for water resistance is b= 100 N-sec/m and the mass of the sailboat is 50 kg, find the equation of motion of the sailboat. What is the limiting velocity of the sailboat under this wind?

Short Answer

Expert verified
  • The equation of motion of sail boat isx(t)=6t+52e-2t-52 .
  • The limiting velocity is 6 m/sec.

Step by step solution

01

Find the equation of velocity 

There are two forces are

F=600F2=-100v

Now

mdvdt=600-100v50dvdt=600-100vdvdt=12-2vdv6-v=2dt-6ln6-v=t+Cv(t)=6-Ce-2t

Put v(0) = 1 then C = 5

v(t)=6-5e-2t

02

Find the value of equation of motion

x(t)=6-5e-2tdtx(t)=6t+5e-2t2+A

When t = 0 then

x(t)=6t+5e-2t2+52

Hence, the equation of motion of sail boat is role="math" localid="1664210783875" x(t)=6t+5e-2t2+52.

The limiting velocity of the sailboat is

limv(t)t=limt(6-5e-2t)=6

Hence, the Limiting velocity is 6 m/sec.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose the snowball in Problem 21 melts so that the rate of change in its diameter is proportional to its surface area. Using the same given data, determine when its diameter will be 2 in. Mathematically speaking, when will the snowball disappear?

Building Temperature.In Section 3.3 we modeled the temperature inside a building by the initial value problem (13)\(\frac{{{\bf{dT}}}}{{{\bf{dt}}}}{\bf{ = K}}\,\,\left[ {{\bf{M}}\,{\bf{(t) - T}}\,{\bf{(t)}}} \right]{\bf{ + H}}\,{\bf{(t) + U}}\,{\bf{(t),}}\,\,{\bf{T}}\,{\bf{(}}{{\bf{t}}_{\bf{o}}}{\bf{) = }}{{\bf{T}}_{\bf{o}}}\) , where M is the temperature outside the building, T is the temperature inside the building, H is the additional heating rate, U is the furnace heating or air conditioner cooling rate, K is a positive constant, and \({{\bf{T}}_{\bf{o}}}\) is the initial temperature at time \({{\bf{t}}_{\bf{o}}}\) . In a typical model, \({{\bf{t}}_{\bf{o}}}{\bf{ = 0}}\) (midnight),\({{\bf{T}}_{\bf{o}}}{\bf{ = 6}}{{\bf{5}}^{\bf{o}}}\), \({\bf{H}}\left( {\bf{t}} \right){\bf{ = 0}}{\bf{.1}}\), \({\bf{U(t) = 1}}{\bf{.5}}\left[ {{\bf{70 - T(t)}}} \right]\)and \({\bf{M(t) = 75 - 20cos}}\frac{{{\bf{\pi t}}}}{{{\bf{12}}}}\) . The constant K is usually between\(\frac{{\bf{1}}}{{\bf{4}}}{\bf{and}}\frac{{\bf{1}}}{{\bf{2}}}\), depending on such things as insulation. To study the effect of insulating this building, consider the typical building described above and use the improved Euler’s method subroutine with\({\bf{h = }}\frac{{\bf{2}}}{{\bf{3}}}\) to approximate the solution to (13) on the interval \(0 \le {\bf{t}} \le 24\) (1 day) for \({\bf{k = 0}}{\bf{.2,}}\,{\bf{0}}{\bf{.4}}\), and 0.6.

Determine the recursive formulas for the Taylor method of order 4 for the initial value problem y'=x2+y,y(0)=0.

Determine the recursive formulas for the Taylor method of order 2 for the initial value problemy'=cos(x+y),y(0)=π.

Show that when the trapezoid scheme given in formula (8) is used to approximate the solutionf(x)=exofy'=y,y(0)=1 , at x = 1, then we get yn+1=1+h21-h2yn,n = 0, 1, 2, . . . , which leads to the approximation (1+h21-h2)1hfor the constant e.Compute this approximation for h= 1,10-1,10-2,10-3,and10-4and compare your results with those in Tables 3.4 and 3.5.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free