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Decide whether or not the method of undetermined coefficients can be applied to find a particular solution of the given equation.2ω''(x)-3ω(x)=4xsin2x+4xcos2x

Short Answer

Expert verified

Yes, the method of undetermined coefficients can be applied.

Step by step solution

01

Simplification of the given differential equation. 

Given equation,

2ω''(x)-3ω(x)=4xsin2x+4xcos2x

Simplify the above equation,

2ω''(x)-3ω(x)=4x(sin2x+cos2x)2ω''(x)-3ω(x)=4x                              ......(1)

02

Now find the roots of the auxiliary equation.

Write the homogeneous differential equation of the equation (1),

2ω''(x)-3ω(x)=0

The auxiliary equation for the above equation,

role="math" localid="1654859563585" 2m2-3=02m2=3m=±32

The roots of the auxiliary equation are,

role="math" localid="1654859598798" m1=32,      m2=-32

The complementary solution of the given equation is,

ωc(x)=c1e32x+c2e-32x.

03

Final conclusion

The R.H.S. of equation is (4x).

Therefore, the particular solution of the equation,

yp(x)=Ax+b

So, the method of undetermined coefficients can be applied.

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