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Question: Let f(x)and g(x)be analytic at x0. Determine whether the following statements are always true or sometimes false:

(a) 3f(x)+g(x)is analytic at x0.

(b) f(x)/g(x)is analytic at x0.

(c) f'(x)is analytic at x0.

(d) f(x)3-x0xg(t)dt is analytic at x0.

Short Answer

Expert verified
  1. Always true.
  2. Sometimes False.
  3. Always true.
  4. Always true

Step by step solution

01

Power series

A power series is an infinite series of the form,n=0an(x-c)n=a0+a1(x-c)+a2(x-c)n+.....

Where, anrepresents the coefficient term of the nth term,c is a constant.

02

Solution for part (a)

It is given that the functions f(x) and g(x) are both analytic at x=x0,therefore both the functions can be written in the form of power series and are convergent in the vicinity of x0

The given function 3f(x)+g(x

The above linear combination of the analytic functions will always hold true because the resultant function will also have a power series representation, this follows directly from the property of summation.) .

03

Solution for part (b)

The given function f(x)g(x).

The above resultant function will hold true only if the denominator g(x)0, therefore, it may be sometimes false.

04

Solution for part (c)

The given function f'(x).

The derivative of the analytic function will also be analytic, as the analytic function have every order of derivative at the point x0 therefore the derivatives of analytic functions will also be analytic. Thus this will always be true.

05

Solution for part (d)

The given function

The above combination of analytic functions will always be analytic, as the operations performed on the functions result in analytic functions. The function f(x) is multiplied three times which will give another analytic function and the function g(x) is integrated, the term-wise integration of the analytic function will also yield another analytic function.

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Most popular questions from this chapter

Variation of Parameters. Here is another procedure for solving linear equations that is particularly useful for higher-order linear equations. This method is called variation of parameters. It is based on the idea that just by knowing the form of the solution, we can substitute into the given equation and solve for any unknowns. Here we illustrate the method for first-order equations (see Sections 4.6 and 6.4 for the generalization to higher-order equations).

(a) Show that the general solution to (20)dydx+P(x)y=Q(x) has the formy(x)=Cyh(x)+yp(x),whereyh ( 0is a solution to equation (20) when Q(x)=0,

C is a constant, andyp(x)=v(x)yh(x) for a suitable function v(x). [Hint: Show that we can takeyh=μ-1(x) and then use equation (8).] We can in fact determine the unknown function yhby solving a separable equation. Then direct substitution of vyh in the original equation will give a simple equation that can be solved for v.

Use this procedure to find the general solution to (21) localid="1663920708127" dydx+3xy=x2, x > 0 by completing the following steps:

(b) Find a nontrivial solutionyh to the separable equation (22) localid="1663920724944" dydx+3xy=0, localid="1663920736626" x>0.

(c) Assuming (21) has a solution of the formlocalid="1663920777078" yp(x)=v(x)yh(x) , substitute this into equation (21), and simplify to obtain localid="1663920789271" v'(x)=x2yh(x).

d) Now integrate to getlocalid="1663920800433" vx

(e) Verify thatlocalid="1663920811828" y(x)=Cyh(x)+v(x)yh(x) is a general solution to (21).

Question: In Problems 29–34, determine the Taylor series about the point X0for the given functions and values of X0.

31. f(x)=1+x1-x.x0 = 0 ,

Show thatϕx=c1sinx+c2cosx, is a solution tod2ydx2+y=0 for any choice of the constantsc1andc2. Thus,c1sinx+c2cosx, is a two-parameter family of solutions to the differential equation.

In problems 1-6, identify the independent variable, dependent variable, and determine whether the equation is linear or nonlinear.

y3d2xdy2+3x-8y-1=0

In Problems 14–24, you will need a computer and a programmed version of the vectorized classical fourth-order Runge–Kutta algorithm. (At the instructor’s discretion, other algorithms may be used.)†

Using the vectorized Runge–Kutta algorithm, approximate the solution to the initial value problem

dudx=3u-4v;u(0)=1'dvdx=2u-3v;v(0)=1

at x = 1. Starting with h=1, continue halving the step size until two successive approximations of u(1)and v(1) differ by at most 0.001.

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