Chapter 8: Problem 72
Show that every standard unit vector \(e_{i}\) is a strongly exposed point of \(B_{\ell_{1}}\).
Short Answer
Expert verified
The functional \( f(x) = x_i \) uniquely maximizes at \( e_i \), proving \( e_i \) is a strongly exposed point of \( B_{\ell_1} \).
Step by step solution
01
Understand the Problem
Given the standard unit vector in the form of \( e_i = (0, 0, ..., 1, ..., 0) \) where 1 is located at the i-th position, determine if it is a strongly exposed point of the \( \ell_1 \)-unit ball, \( B_{\ell_1} \).
02
Define Strongly Exposed Point
A point \( x \) in a convex set \( C \) is said to be a strongly exposed point if there exists a functional \( f \) such that for all sequences \( x_n \in C \) converging to \( x \), the functional \( f(x_n) \) strictly decreases as \( x_n \) moves away from \( x \).
03
Identify the Functional
Consider the functional \( f(x) = x_i \). This functional will attain its maximum value at \( e_i \), that is, \( f(e_i) = 1 \).
04
Show Uniqueness
This functional attains its maximum value of 1 only at the point \( e_i \). Suppose there is another vector \( y = (y_1, y_2, ..., y_i, ..., y_n) \) where \( f(y) = 1 \). This would imply \( y_i = 1 \) and since \( \sum |y_j| \leq 1 \), all other \( y_j =0 \). Therefore, \( y = e_i \), proving the uniqueness.
05
Conclusion
Since \( f(x) \), the functional defined above, uniquely maximizes at \( e_i \), \( e_i \) is a strongly exposed point of \( B_{\ell_1} \) by definition.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
strongly exposed point
In functional analysis, a strongly exposed point is a specific type of point within a convex set. It often relates to the behavior of functionals. By definition, a point x in a convex set C is strongly exposed if there exists a supporting hyperplane or functional that uniquely attains its maximum at this point.
Imagine navigating a 3D shape; if you find just one spot where a plane touches it, that could be a strongly exposed point.
Essential characteristics include:
Imagine navigating a 3D shape; if you find just one spot where a plane touches it, that could be a strongly exposed point.
Essential characteristics include:
- Existence of a unique supporting functional.
- Uniqueness in attaining the maximal value.
functional
A functional is a map from a vector space to the field of scalars (real or complex numbers). It's a foundational concept in functional analysis.
Think of it as a special kind of function that takes a vector as input and produces a single scalar as output.
Think of it as a special kind of function that takes a vector as input and produces a single scalar as output.
- Mathematically, if V is a vector space over the field F, a functional f maps each element of V to an element of F: f: V → F.
- In the given problem, the functional f(x) = x_i was used.
convex set
A convex set is a subset of a vector space that contains all line segments between any two points within the set. This implies no indentations or holes.
- If you pick any two points in a convex set, the line segment joining them also lies entirely within the set.
- Examples include simple shapes like line segments, circles, and convex polygons.
unit vector
A unit vector is a vector with a magnitude of exactly 1. It's often used to describe directions in space because it has no scale distortion.
- In the context of the problem, standard unit vectors have exactly one component equal to 1 and all others equal to 0.
- For example, in \( \mathbb{R}^3 \), one of the unit vectors is \( (1, 0, 0) \).
unit ball
A unit ball in a normed vector space is the set of all vectors whose norm (or length) is less than or equal to one. It provides a way to visualize the 'size' of elements within the space.
- For \( \ell_1 \)-norm, the unit ball is defined as \( \{ x \in \mathbb{R}^n : \sum_{i=1}^{n} |x_i| \leq 1 \} \).
- In 2D, this looks like a diamond shape rather than a circular ball.