Chapter 8: Problem 7
Let \(f, g\) be convex continuous functions on a Banach space \(X\) and assume that \(f\) is not Fréchet differentiable at \(x \in X .\) Show that \(f+g\) is not Fréchet differentiable at \(x\). Hint: By the assumption, \(f(x+h)+f(x-h)-2 f(x) \geq \varepsilon h\).
Short Answer
Expert verified
Since \( f(x+h) + f(x-h) - 2f(x) \geq \varepsilon \|h\| \), \( f+g \) is not Fréchet differentiable at \( x \).
Step by step solution
01
Define Fréchet differentiability
A function is Fréchet differentiable at a point if it can be approximated by a linear map in the neighborhood of that point. Formally, if there exists a bounded linear operator A such that \[ \lim_{\|h\| \to 0} \frac{\| f(x+h) - f(x) - A(h) \|}{\|h\|} = 0 \].
02
Consider the given condition for f
The condition given in the problem hints that \( f(x+h) + f(x-h) - 2f(x) \geq \varepsilon \|h\| \), for a certain \( \varepsilon > 0 \) and for all small \( h \). This implies that \( f(x+h) \) is not linearly approximable around \( x \).
03
Analyze the combined function f + g
We need to investigate the behavior of \(f+g\) around \(x\). Using the information from the previous steps, let's observe: \( (f+g)(x+h) + (f+g)(x-h) - 2(f+g)(x) \).
04
Express the combined function
We can rewrite the expression as: \( f(x+h) + g(x+h) + f(x-h) + g(x-h) - 2f(x) - 2g(x) \).
05
Apply the given condition
Since \( f(x+h) + f(x-h) - 2f(x) \geq \varepsilon \|h\| \), we can substitute this into our expression: \( \varepsilon \|h\| + g(x+h) + g(x-h) - 2g(x) \).
06
Recognize the behavior of g
Since \( g \) is convex and continuous, \( g(x+h) + g(x-h) - 2g(x) \geq 0 \).
07
Conclude non-differentiability
Combining both results, we get: \( (f+g)(x+h) + (f+g)(x-h) - 2(f+g)(x) \geq \varepsilon \|h\| \), which implies that \( f+g \) is also not linearly approximable around \( x\). Therefore, \( f+g \) is not Fréchet differentiable at \( x \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Banach Space
A Banach space is a complete normed vector space. This means it is a vector space equipped with a norm, and every Cauchy sequence in this space converges within the space.
In simpler terms, if you are working within a Banach space, you are assured that all the sequences that should converge, will indeed find their limit inside the space.
Here are some key points to remember about Banach spaces:
Understanding Banach spaces is crucial in advanced mathematics, as they allow the generalization of many important concepts from finite-dimensional spaces to infinite-dimensional ones.
In simpler terms, if you are working within a Banach space, you are assured that all the sequences that should converge, will indeed find their limit inside the space.
Here are some key points to remember about Banach spaces:
- The space is linear, meaning it respects addition and scalar multiplication.
- The norm assigns a length to each vector.
- Completeness ensures that certain well-behaved sequences are bound to converge within the space.
Understanding Banach spaces is crucial in advanced mathematics, as they allow the generalization of many important concepts from finite-dimensional spaces to infinite-dimensional ones.
Convex Functions
Convex functions play a major role in optimization and analysis. A function is convex if the line segment between any two points on the graph of the function lies above or on the graph.
Mathematically, a function \(f\) is convex if for any points \(x, y\) in its domain and \(t \in [0, 1]\), the following holds:
\[ f(tx + (1-t)y) \leq t f(x) + (1-t) f(y) \]
This property is vital because it ensures there are no local minima other than the global minimum, making them easier to analyze and optimize.
Key properties of convex functions include:
Mathematically, a function \(f\) is convex if for any points \(x, y\) in its domain and \(t \in [0, 1]\), the following holds:
\[ f(tx + (1-t)y) \leq t f(x) + (1-t) f(y) \]
This property is vital because it ensures there are no local minima other than the global minimum, making them easier to analyze and optimize.
Key properties of convex functions include:
- If the second derivative of a function is non-negative everywhere, the function is convex.
- Convex functions are closed under addition, meaning the sum of convex functions is also convex.
- Convexity helps in analyzing the behavior of complex functions, especially when dealing with optimization problems.
Differentiation
Differentiation is the process of finding the derivative of a function. The derivative measures how a function changes as its input changes.
When talking about Fréchet differentiability, we're extending the idea of differentiation to functions between Banach spaces.
A function \(f: X \to Y\) between Banach spaces is Fréchet differentiable at a point \(x \in X\) if there exists a bounded linear operator \(A: X \to Y\) that closely approximates the change in \(f\).
Formally, \[ \lim_{\|h\| \to 0} \frac{\| f(x+h) - f(x) - A(h) \|}{\|h\|} = 0 \]
What this means is that near \(x\), the function \(f\) can be well-approximated by a linear map.
Important aspects of Fréchet differentiability include:
When talking about Fréchet differentiability, we're extending the idea of differentiation to functions between Banach spaces.
A function \(f: X \to Y\) between Banach spaces is Fréchet differentiable at a point \(x \in X\) if there exists a bounded linear operator \(A: X \to Y\) that closely approximates the change in \(f\).
Formally, \[ \lim_{\|h\| \to 0} \frac{\| f(x+h) - f(x) - A(h) \|}{\|h\|} = 0 \]
What this means is that near \(x\), the function \(f\) can be well-approximated by a linear map.
Important aspects of Fréchet differentiability include:
- It's a stronger form of differentiability compared to Gâteaux differentiability, which only requires the directional derivative to exist.
- It guarantees that the approximation by the linear operator is uniform in all directions.
- In practical terms, it ensures smoother behaviors and helps in simplifying complex function analyses.