Chapter 8: Problem 42
Let \(X, Y\) be Banach spaces, and let \(T\) be an isometric mapping of \(X\) onto \(Y\). The Mazur-Ulam theorem claims that if \(T(0)=0\), then \(T\) is necessarily linear. Show this result for the case when \(Y\) is strictly convex.
Short Answer
Expert verified
Since T is isometric and Y is strictly convex, T must preserve linear structure due to distance preservation and strict convexity properties, proving T is linear.
Step by step solution
01
Understand Isometric Mapping
An isometric map preserves distances. For a map T: X → Y, this means that for all x1, x2 ∈ X, the equality \(\|T(x1) - T(x2)\|_Y = \|x1 - x2\|_X\) holds.
02
Use the Property T(0)=0
Since T(0) = 0, the mapping keeps 0 fixed. This is essential since it suggests T(b) = b for some b in Y when we compare image distances.
03
Apply the Mazur-Ulam Theorem
The Mazur-Ulam theorem states that if T is an isometric mapping that fixes 0, then T is linear. We need to show that this applies in the strictly convex case.
04
Consider the Strict Convexity of Y
In a strictly convex space, the midpoint of two distinct points lies strictly inside the line segment joining these points. Formally, if \(||z_1|| = ||z_2|| = 1\), and \(z_1 eq z_2 \), then \(||\frac{z_1+z_2}{2}|| < 1\).
05
Prove T is Linear
To prove linearity, consider two points x, y in X. By the properties of isometric maps and strict convexity: \[\begin{aligned} \|T(x + y)\|_Y & = \|x + y\|_X , \ \|T(x) + T(y)\|_Y & \leq \|T(x)\|_Y + \|T(y)\|_Y = \|x\|_X + \|y\|_X = \|x + y\|_X. \end{aligned}\] By strict convexity, \(\|T(x) + T(y)\|_Y = \|T(x + y)\|_Y\) must hold. This implies \(T(x + y) = T(x) + T(y)\).
06
Verify Homogeneity
Lastly, for any scalar \(\alpha\) and vector \(x\), note that \[ T(\alpha x) = \alpha T(x) \] using similar distance-preserving logic and strict convexity, confirming both properties of linearity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Banach Spaces
A Banach space is a vector space equipped with a norm, which is complete concerning this norm. This means that any Cauchy sequence in the space will converge to a point within the same space. Examples of Banach spaces include spaces like \(L^p\) spaces for \(p \geq 1 \), where functions are defined with a specific integrable power.
Banach spaces are central in functional analysis because their completeness property ensures that the limit of a sequence of vectors behaves well under various operations.
This stability is crucial when dealing with mappings and transformations, ensuring that the results hold within the space.
Banach spaces are central in functional analysis because their completeness property ensures that the limit of a sequence of vectors behaves well under various operations.
This stability is crucial when dealing with mappings and transformations, ensuring that the results hold within the space.
- Vector space: A collection of vectors where addition and scalar multiplication are defined.
- Norm: A function assigning a non-negative length or size to each vector.
- Cauchy sequence: A sequence where the elements get closer to each other as the sequence progresses.
- Completeness: Every Cauchy sequence converges within the space.
Isometric Mapping Explained
An isometric mapping is a function that preserves distances. This means if you measure the distance between two points in the source space and map those points to a target space, the distance between the images of these points remains unchanged.
Formally, for an isometric map \( T: X \rightarrow Y \), we have: \( \|T(x_1) - T(x_2)\|_Y = \|x_1 - x_2\|_X \) for all \( x_1, x_2 \in X \). This equality indicates that the structure or 'shape' of the space is preserved under the mapping.
An essential aspect of isometric mappings is that they are not only distance-preserving but also injective (one-to-one), meaning every point in the source space has a unique corresponding point in the target space.
Formally, for an isometric map \( T: X \rightarrow Y \), we have: \( \|T(x_1) - T(x_2)\|_Y = \|x_1 - x_2\|_X \) for all \( x_1, x_2 \in X \). This equality indicates that the structure or 'shape' of the space is preserved under the mapping.
An essential aspect of isometric mappings is that they are not only distance-preserving but also injective (one-to-one), meaning every point in the source space has a unique corresponding point in the target space.
- Preserving distances: The key property of isometric mappings.
- Injective: Each point in the source space maps to a unique point in the target space.
- Norm invariance: The norm of the difference between two points remains the same when mapped.
Strict Convexity in Spaces
A space is strictly convex if, for any two distinct points within a unit ball, the midpoint of the line segment joining these points lies strictly inside the unit ball. Mathematically, for \( \|z_1\| = \|z_2\| = 1 \) and \( z_1 \e z_2 \), we have \( \|\frac{z_1 + z_2}{2}\| < 1 \).
This property ensures that the space does not have any 'flat' parts on its boundary and encourages uniqueness in the configurations. In other words, combining points always results in points that do not stay on the boundary but lie strictly inside.
This property ensures that the space does not have any 'flat' parts on its boundary and encourages uniqueness in the configurations. In other words, combining points always results in points that do not stay on the boundary but lie strictly inside.
- Midpoint property: The midpoint of any two distinct points lies inside the segment.
- Uniqueness: Helps in ensuring properties like the linearity of isometric maps.