Chapter 3: Problem 64
Let \(Y\) be a closed subspace of a Banach space \(X .\) Show that if \(Y\) and \(X / Y\) are reflexive, then \(X\) is reflexive. Thus, reflexivity is a three-space property.
Short Answer
Expert verified
If \(Y\) and \(X/Y\) are reflexive, then \(X\) is reflexive because the natural map \(X \rightarrow X^{**}\) becomes surjective, proving the reflexivity.
Step by step solution
01
Understand Reflexivity
A Banach space is reflexive if the natural map from the space to its double dual is surjective. That is, every bounded linear functional on the dual can be represented by an element of the space itself.
02
Consider Given Conditions
We know that both subspace \(Y\) and the quotient space \(X/Y\) are reflexive. We need to show that this implies \(X\) is reflexive.
03
Use the Fact The Dual of \(X/\)Y Is Isomorphic to X Mo dulo \(Y^\bot\)
A key fact is that \((X/Y)^* eq Y^\bot\). This means $$(X/Y)^* eq Y^\bot$$ is hints isomorphic to the annihilator of \(Y\) in \(X^*\). Hence the duality plays a role.
04
Reflexivity Property Transfer
Given that \(Y\) is reflexive, \(Y^{**} egets Y\). Also since \(X / Y\) is reflexive \(((X/Y)^* * = X* / Y)^*= X/Y\). This is important because it means the duals share reflexivity.
05
Use Hahn-Banach Theorem
The Hahn-Banach theorem can give insight into reflexivity.
06
Show Surjectivity
We must show that the natural inclusion map \(X \rightarrow X^{**}\) is surjective. Utilizing those reflexivities and nature of closed embedded space, we can show that the map \(X \rightarrow X^{**}\) is onto.
07
Conclude Reflexivity
Since we have shown that \(X \rightarrow X^{**}\) is surjective, we conclude that \(X\) is reflexive, thus proving that reflexivity is a three-space property.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Banach spaces
Banach spaces are complete normed vector spaces. This means every Cauchy sequence in the space converges to an element within the space. Banach spaces are crucial in functional analysis because they provide a framework where many important theorems and operations are valid.
For instance:
For instance:
- Given any continuous linear map from a Banach space to another, the image is also a Banach space if the map is surjective.
- Norms in Banach spaces lead to metric structures, making them akin to metric spaces with practical applications in solving differential equations.
Reflexivity
A Banach space is reflexive if the natural embedding into its double dual is surjective. This means every bounded linear functional on the dual can be identified with an element of the space itself. Reflexivity implies that:
- The weak topology and weak* topology on the dual space coincide.
- Any bounded sequence in a reflexive Banach space has a weakly convergent subsequence.
Hahn-Banach theorem
The Hahn-Banach theorem is a cornerstone in functional analysis. It allows us to extend bounded linear functionals from a subspace to the whole space while preserving their norm. This theorem is used to demonstrate many other fundamental results:
- It shows the existence of supporting hyperplanes in convex analysis.
- It extends functionals, allowing the study of dual spaces more comprehensively.
Quotient spaces
Quotient spaces form a core concept in analyzing Banach spaces. Given a Banach space \(X\) and a closed subspace \(Y\), the quotient space \(X/Y\) is the set of cosets of \(Y\) in \(X\), equipped with a norm derived from \(X\). Important properties include:
- \(X/Y\) is also a Banach space.
- The dual of \(X/Y\) relates to the annihilator of \(Y\) in the dual space \(X^*\). This connection is crucial in examining reflexive properties through quotient and subspaces.
Dual spaces
The dual space of a Banach space \(X\) (denoted as \(X^*\)) consists of all bounded linear functionals on \(X\). This space is vital because it facilitates:
- Analyzing continuous linear functionals and operator theory.
- Understanding the weak and weak* topologies, influencing convergence and compactness properties in Banach spaces.