Chapter 1: Problem 40
Let \(X\) be a Banach space whose norm \(\|\cdot\|\) satisfies the parallelogram equality. Define \((x, y)\) by the polarization identity, and prove that \((x, y)\) is an inner product. Hint: Clearly, \(\left(\cdot_{1} \cdot\right)\) is continuous in both coordinates, \((x, y)=\overline{(y, x)}\) and \((-x, y)=-(x, y)\). Using the parallelogram equality, show that \((x+y, z)=\) \((x, z)+(y, z)\). Then by induction, \((n x, y)=n(x, y)\) for all \(n \in \mathbf{N}\), and hence also for all integers \(n\). Given \(\frac{n}{m}\), we have \(\left(\frac{n}{m} x, y\right)=n\left(\frac{1}{m} x, y\right)=\frac{n}{m} m\left(\frac{1}{m} x, y\right)=\frac{n}{m}\left(\frac{m}{m} x, y\right)=\) \(\frac{n}{m}(x, y)\). By continuity, we get \((\alpha x, y)=\alpha(x, y)\) for all \(\alpha \in \mathbf{R}\).
Short Answer
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