Chapter 1: Problem 35
We say that \(\sum x_{i}\) is unconditionally Cauchy if, given \(\varepsilon>0\), there is a finite set \(F\) in \(\mathbf{N}\) such that \(\left\|\sum_{F^{\prime}} x_{i}\right\|<\varepsilon\) whenever \(F^{\prime}\) is a finite set in \(\mathbf{N}\) satisfying \(F^{\prime} \cap F=\emptyset\) Show that a series \(\sum x_{i}\) in a Banach space \(X\) is unconditionally Cauchy if and only if it is unconditionally convergent. Hint: If \(\sum x_{i}\) is unconditionally Cauchy, then it is Cauchy and thus it converges to some \(x \in X\). Given \(\varepsilon>0\), find a finite \(F_{1}\) such that \(\left\|\sum_{\vec{F}^{\prime}} x_{i}\right\|<\varepsilon\) for every finite \(F^{\prime}\) satisfying \(F^{\prime} \cap F_{1}=\emptyset\). Then find \(n_{0}>\max \left(F_{1}\right)\) such that \(\left\|\sum_{i=1}^{n_{0}} x_{i}-x\right\|<\varepsilon\) and set \(F=\left\\{1, \ldots, n_{0}\right\\}\). If \(F^{\prime} \supset F\), then \(\left\\{i \in F^{\prime} ; i\right\rangle\) \(\left.n_{0}\right\\} \cap F_{1}=\emptyset\), so \(\left\|\sum_{F^{\prime}} x_{i}-x\right\| \leq\left\|_{i \in F^{\prime}, i>n_{0}} x_{i}-x\right\|+\left\|\sum_{i=1}^{n_{0}} x_{i}\right\|<2 \varepsilon\)
Short Answer
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Key Concepts
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