Chapter 3: Problem 4
Using the generalized Plancherel identity, calculate the integral $$ \int_{0}^{\infty} \frac{d t}{\left(a^{2}+t^{2}\right)\left(b^{2}+t^{2}\right)}, \quad a, b>0 . $$
Short Answer
Expert verified
\( \frac{\pi(b-a)}{2ab(b+a)} \)
Step by step solution
01
Understand the Integral's Structure
We need to calculate the integral \( \int_{0}^{\infty} \frac{dt}{(a^2+t^2)(b^2+t^2)} \). The integral involves rational functions with two quadratic terms in the denominator.
02
Use Partial Fraction Decomposition
Express \( \frac{1}{(a^2+t^2)(b^2+t^2)} \) as a sum of partial fractions: \( \frac{A}{a^2+t^2} + \frac{B}{b^2+t^2} \), and solve for \( A \) and \( B \).
03
Solve for Constants A and B
Set \( 1 = A(b^2+t^2) + B(a^2+t^2) \). By matching coefficients, solve for \( A = \frac{1}{b^2-a^2} \) and \( B = -\frac{1}{b^2-a^2} \).
04
Integrate Each Term Separately
The integral becomes two separate integrals: \( \int_0^\infty \frac{\frac{1}{b^2-a^2}}{a^2+t^2} dt - \int_0^\infty \frac{\frac{1}{b^2-a^2}}{b^2+t^2} dt \).
05
Use Standard Integral Form
Recall the standard integral \( \int_0^\infty \frac{dt}{t^2+x^2} = \frac{\pi}{2x} \). Apply this formula to each term: the first becomes \( \frac{\pi}{2a} \frac{1}{b^2-a^2} \) and the second \( \frac{\pi}{2b} \frac{1}{b^2-a^2} \).
06
Simplify the Expression
Combine the two results: \( \frac{\pi}{2(b^2-a^2)} \left( \frac{1}{a} - \frac{1}{b} \right) \).
07
Final Result
Simplifying further, we obtain the final result: \( \frac{\pi(b-a)}{2ab(b+a)} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Plancherel Identity
The Plancherel identity is a deep result in Fourier analysis that connects the field of signal processing to the mathematical study of functions. It essentially states that the Fourier transform is an energy-preserving transformation. This means that the total energy of a signal is identical whether the signal is measured in the time domain or in the frequency domain.
This identity is formally expressed as:
This identity is formally expressed as:
- The integral of the square of a function equals the integral of the square of its Fourier transform.
- This expression implies that certain calculations, such as integrals of rational functions, might be solved more easily by transforming them.
Partial Fraction Decomposition
Partial fraction decomposition is a technique used to simplify the integration of rational functions. For a complex fraction, it's broken into simpler fractions, which can be more straightforward to integrate separately.
In the exercise, the fraction \( \frac{1}{(a^2+t^2)(b^2+t^2)} \) is decomposed into two simpler fractions: \( \frac{A}{a^2+t^2} + \frac{B}{b^2+t^2} \). Here, the constants \( A \) and \( B \) are chosen to satisfy:
In the exercise, the fraction \( \frac{1}{(a^2+t^2)(b^2+t^2)} \) is decomposed into two simpler fractions: \( \frac{A}{a^2+t^2} + \frac{B}{b^2+t^2} \). Here, the constants \( A \) and \( B \) are chosen to satisfy:
- Make the equality hold across the whole expression.
- This step makes integration easier for each part separately.
Integral Calculus
Integral calculus is fundamental in mathematics for finding quantities like areas under curves or solving differential equations.
In this exercise, integral calculus provides methods to approach and solve the integration problem by using different techniques and transformations:
In this exercise, integral calculus provides methods to approach and solve the integration problem by using different techniques and transformations:
- The given integral is initially transformed with partial fractions.
- Each part is then tackled using known forms and identities.
Standard Integral Forms
When facing integrals, it's beneficial to know standard integral forms as they serve as shortcuts to quick solutions. These are predefined solutions for common types of integral problems.
In the exercise, the standard integral used is:
In the exercise, the standard integral used is:
- \( \int_0^\infty \frac{dt}{t^2+x^2} = \frac{\pi}{2x} \)