Chapter 2: Problem 3
Let
$$
f(x)= \begin{cases}A \sin \omega_{0} t, & 0
Short Answer
Expert verified
Compute coefficients \( C_n \) using integrals; sum them for the series.
Step by step solution
01
Understand the Problem Statement
We need to find the complex Fourier series of the piecewise function \( f(t) \). The function \( f(t) \) is defined as \( A \sin \omega_0 t \) for \( 0 < t < \frac{T}{2} \) and as 0 for \( \frac{T}{2} \leq t < T \). The parameter \( \omega_0 = \frac{2\pi}{T} \) is the fundamental angular frequency.
02
Determine the Formula for the Complex Fourier Series
The complex Fourier series for a function on the interval \([0, T]\) is defined as: \[ f(t) = \sum_{n=-\infty}^{\infty} C_n e^{i n \omega t}, \] where \( C_n \) are the Fourier coefficients given by \[ C_n = \frac{1}{T} \int_{0}^{T} f(t) e^{-i n \omega t} \, dt. \] Here, \( \omega = \frac{2\pi}{T} \).
03
Calculate Fourier Coefficients \( C_n \)
We calculate \( C_n \) by breaking the integral into two parts due to the piecewise definition of \( f(t) \): \[ C_n = \frac{1}{T} \left( \int_{0}^{\frac{T}{2}} A \sin \left( \frac{2\pi}{T}t \right) e^{-i n \omega t} \right. dt + \left. \int_{\frac{T}{2}}^{T} 0 \, dt \right). \] The second integral is zero due to the zero function between \( \frac{T}{2} \) and \( T \). Thus, \[ C_n = \frac{A}{T} \int_{0}^{\frac{T}{2}} \sin \left( \frac{2\pi}{T}t \right) e^{-i n \omega t} \, dt. \]
04
Simplify the Integral
The integral can be solved by using the identity for sine in terms of exponentials: \[ \sin(\omega_0 t) = \frac{e^{i \omega_0 t} - e^{-i \omega_0 t}}{2i}. \]This leads to: \[ C_n = \frac{A}{2iT} \int_{0}^{\frac{T}{2}} \left( e^{i \omega_0 t} - e^{-i \omega_0 t} \right) e^{-i n \omega t} \, dt. \] Breaking this into two integrals yields:\[ C_n = \frac{A}{2iT} \left( \int_{0}^{\frac{T}{2}} e^{i(\omega_0 - n\omega)t} \, dt - \int_{0}^{\frac{T}{2}} e^{-i(\omega_0 + n\omega)t} \, dt \right). \]
05
Evaluate the Integrals
Each integral is of the form \( \int e^{i \alpha t} \, dt \), which results in:\[ \int e^{i \alpha t} \, dt = \frac{e^{i \alpha t}}{i \alpha}. \] Applying this, we compute:\[ \int_{0}^{\frac{T}{2}} e^{i(\omega_0 - n\omega)t} \, dt = \frac{e^{i(\omega_0 - n\omega)\frac{T}{2}} - 1}{i(\omega_0 - n\omega)}, \] \[ \int_{0}^{\frac{T}{2}} e^{-i(\omega_0 + n\omega)t} \, dt = \frac{1 - e^{-i(\omega_0 + n\omega)\frac{T}{2}}}{i(\omega_0 + n\omega)}. \]
06
Simplify the Coefficient Expression
Substitute the results back into the expression for \( C_n \):\[ C_n = \frac{A}{2iT} \left( \frac{e^{i(\omega_0 - n\omega)\frac{T}{2}} - 1}{i(\omega_0 - n\omega)} - \frac{1 - e^{-i(\omega_0 + n\omega)\frac{T}{2}}}{i(\omega_0 + n\omega)} \right). \]Simplify to obtain the final expression for \( C_n \).
07
Write the Final Fourier Series Expression
Combine all the coefficients to write the final form of the complex Fourier series:\[ f(t) = \sum_{n=-\infty}^{\infty} C_n e^{i n \omega t}, \] using the expressions derived for \( C_n \). Simplify if possible, using trigonometric identities or symmetries to express the series in the simplest form.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Complex Fourier Series
The complex Fourier series is a powerful tool in mathematical analysis used to express periodic functions as an infinite sum of complex exponentials. It holds significance because it provides a comprehensive way to represent functions in the frequency domain.
The basic form of the complex Fourier series on an interval \([0, T]\) is:
By using complex exponentials, a broader range of applications is facilitated, particularly in engineering and physics, where understanding phase shifts and oscillations is crucial.
The basic form of the complex Fourier series on an interval \([0, T]\) is:
- \( f(t) = \sum_{n=-\infty}^{\infty} C_n e^{i n \omega t} \)
By using complex exponentials, a broader range of applications is facilitated, particularly in engineering and physics, where understanding phase shifts and oscillations is crucial.
Fourier Coefficients
Fourier coefficients \( C_n \) are the building blocks of Fourier series, serving to adjust the amplitude and phase of each term to match the function being represented. They are calculated using the integral formula:
The presence of the exponential \( e^{-i n \omega t} \) acts like a filter, allowing only the specific frequency component corresponding to \( n \) to be analyzed and extracted. In essence, it captures how much of this sinusoidal component is present within the function. The concept is about finding a match in terms of magnitude and phase between the function and pure sine waves.
- \( C_n = \frac{1}{T} \int_{0}^{T} f(t) e^{-i n \omega t} \, dt \)
The presence of the exponential \( e^{-i n \omega t} \) acts like a filter, allowing only the specific frequency component corresponding to \( n \) to be analyzed and extracted. In essence, it captures how much of this sinusoidal component is present within the function. The concept is about finding a match in terms of magnitude and phase between the function and pure sine waves.
Piecewise Function
A piecewise function is a function defined by multiple sub-functions, each applying to a certain interval of the domain. In the context of Fourier series, piecewise functions often introduce discontinuities or changes in behavior over the domain of interest.
The exercise involves a piecewise function given by:
The exercise involves a piecewise function given by:
- \( f(x)= \begin{cases}A \sin \omega_{0} t, & 0
Sine Function Representation
Representing a function using only sine (or cosine) functions is a common application of Fourier series, particularly for periodic signals. Sine functions have properties that make them ideal for capturing oscillatory behaviors, which is fundamental in analyzing sound and waveforms.
In scenarios where the function is piecewise and partly a sine function, as in:
This conversion is crucial in simplifying the integration process when deriving Fourier coefficients and creating more uniform formulas that are applicable in digital signal processing and electrical engineering.
In scenarios where the function is piecewise and partly a sine function, as in:
- \( A \sin \omega_0 t \) for \( 0 < t < \frac{T}{2} \)
This conversion is crucial in simplifying the integration process when deriving Fourier coefficients and creating more uniform formulas that are applicable in digital signal processing and electrical engineering.