Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Plot the dependent variable against the Independent variable. Find the least squares line for this data. What is the Y-intercept? If \(3.0\) units of fertilizer were used what would be a good guess as to the resultant corn yield? $$ \begin{array}{l|l|l|l|l|l|l|l|l|l} \mathrm{X} & \text { Fertilizer } & .3 & .6 & .9 & 1.2 & 1.5 & 1.8 & 2.1 & 2.4 \\\ \hline \mathrm{Y} & \text { Corn Yield } & 10 & 15 & 30 & 35 & 25 & 30 & 50 & 45 \end{array} $$

Short Answer

Expert verified
The least squares line for the given data is \(Y = 28.57X - 8.47\). The Y-intercept is -8.47. When 3.0 units of fertilizer are used, a good guess for the resultant corn yield would be approximately 77.24 units.

Step by step solution

01

Calculate the mean of the variables

First, let's calculate the mean (average) values for both variables. \( \bar{X} = \frac{\sum X_{i}}{n}\) \( \bar{Y} = \frac{\sum Y_{i}}{n}\) where n is the number of observations. Using the given data: n = 8 \( \bar{X} = \frac{0.3 + 0.6 + 0.9 + 1.2 + 1.5 + 1.8 + 2.1 + 2.4}{8} = 1.35\) \( \bar{Y} = \frac{10 + 15 + 30 + 35 + 25 + 30 + 50 + 45}{8} = 30\)
02

Calculate the slope and Y-intercept of the least squares line

Next, we calculate the slope (m) and Y-intercept (b) of the least squares line using the following formulas respectively: \(m = \frac{\sum (X_{i} - \bar{X})(Y_{i} - \bar{Y})}{\sum (X_{i} - \bar{X})^{2}}\) \(b = \bar{Y} - m\bar{X}\) Calculating the slope (m): \( m = \frac{(0.3-1.35)(10-30) + (0.6-1.35)(15-30) + \dots + (2.4-1.35)(45-30)}{(0.3-1.35)^2 + (0.6-1.35)^2 + \dots + (2.4-1.35)^2} = 28.57 \) Calculating the Y-intercept (b): \( b = 30 - 28.57\cdot1.35 = -8.47 \) Now we have the least squares line equation: \(Y = 28.57X - 8.47\)
03

Plot the dependent variable against the independent variable with the least squares' line

Using the dataset and the least squares line equation, plot the dependent variable (corn yield) against the independent variable (fertilizer) and draw the best-fit line.
04

Estimate the corn yield when 3.0 units of fertilizer are used

Now, we will use the least squares line equation to predict the corn yield when 3.0 units of fertilizer are used. Plug X = 3.0 into the equation: \(Y = 28.57(3.0) - 8.47\) \(Y = 77.24\) A good guess for the corn yield when 3.0 units of fertilizer are used would be approximately 77.24 units.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dependent and Independent Variables
Understanding the relationship between dependent and independent variables is a fundamental aspect of linear regression. When we gather data, such as the effect of fertilizer on corn yield, we are often looking for how one variable responds to changes in another.

The independent variable is the one that is changed or controlled in a scientific experiment to test the effects on the dependent variable. In the given exercise, the amount of fertilizer is the independent variable because it's the factor we are changing. Conversely, the dependent variable is what you measure in the experiment and what is affected during the experiment. Here, the corn yield is the dependent variable, as it is the outcome we're investigating.

The two variables have what's called a 'cause and effect' relationship where the independent variable (fertilizer) is the cause and the dependent variable (corn yield) is the effect. This distinction is crucial when plotting data for analysis or interpreting results, as it helps us to understand which variable is influencing the other.
Y-intercept
The Y-intercept of a line in a two-dimensional graph is where the line crosses the Y-axis. It is the value of the dependent variable when the independent variable is zero. This concept is vital when we're dealing with linear equations of the form Y = mX + b, where 'm' is the slope and 'b' is the Y-intercept.

In our case, the Y-intercept can be interpreted as the expected corn yield when no fertilizer is used, which gives us a baseline of our dataset's expected behavior. To calculate the Y-intercept, you use both the slope of the line and the means of X and Y, as shown in the solution. In our exercise, the Y-interceptor (b) was found to be approximately -8.47. This indicates that, with no fertilizer usage, the model predicts a negative corn yield, which is not physically plausible but serves to highlight that the linear model is a simplification and tends to be more accurate within the range of observed data points rather than outside it.
Predicting Outcomes with Linear Regression
Linear regression is a statistical method used to create a linear model that can predict the dependent variable's values based on the independent variable. It involves finding the best-fit line through the data, which is accomplished using the least squares method.

The idea is to minimize the sum of the squares of the vertical distances (residuals) between the observed values and the line’s predicted values. The least squares line then allows us to predict outcomes. As demonstrated in the exercise, with the equation of the least squares line, Y = 28.57X - 8.47, we can predict the corn yield for a given amount of fertilizer. For instance, with 3.0 units of fertilizer, the predicted corn yield would be approximately 77.24 units.

It's important to note that predictions with this method are best used within the range of the data from which the model was created, as extrapolation beyond this range can lead to less reliable predictions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\(\mathrm{Z}\) is a standard normal random variable. \(\mathrm{U}\) is chi-square with \(\mathrm{k}\) degrees of freedom. Assume \(\mathrm{Z}\) and \(\mathrm{U}\) are independent. Using the change of variable technique, find the distribution of \(\mathrm{X}=[\mathrm{Z} / \sqrt{(\mathrm{u} / \mathrm{k})}]\)

Find the expected value and variance of a random variable, $$ \mathrm{Y}=\mathrm{a}_{1} \mathrm{X}_{1}+\mathrm{a}_{2} \mathrm{X}_{2}+\ldots \ldots+\mathrm{a}_{\mathrm{n}} \mathrm{X}_{\mathrm{n}} $$ where the \(\mathrm{X}_{\mathrm{i}}\) are independent and each have mean \(\mu\) and variance \(\sigma^{2}\). The \(a_{i}\) are constants.

In the Idaho State Home for Runaway Girls, 25 residents were polled as to what age they ran away from home. The sample mean was 16 years old with a standard deviation of \(1.8\) years. Establish a \(95 \%\) confidence interval for \(\mu\), the mean age at which runaway girls leave home in Idaho.

Use the Kolmogorov-Smirnov Statistic to find a \(95 \%\) confidence interval for \(\mathrm{F}(\mathrm{x}) . \mathrm{F}(\mathrm{x})\) is the cumulative distribution function of a population from which the following ordered samples was taken: \(8.2,10.4,10.6,11.5,12.6,12.9\), \(13.3,13.3,13.4,13.4,13.6,13.8,14.0,14.0,14.1,14.2\) \(14.6,14.7,14.9,15.0,15.4,15.6,15.9,16.0,16.2,16.3\) 17.2,17.4,17.7,18.1 .$

The simplest continuous random variable is the one whose distribution is constant over some interval \((a, b)\) and zero elsewhere. This is the uniform distribution. $$ \begin{array}{ll} \mathrm{f}(\mathrm{x})=[1 /(\mathrm{b}-\mathrm{a})], & \mathrm{a} \leq \mathrm{X} \leq \mathrm{b} \\ \text { and }=0, & \text { elsewhere } \end{array} $$ Find the mean and variance of this distribution.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free