Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Suppose that \(75 \%\) of the students taking statistics pass the course. In a class of 40 students, what is the expected number who will pass. Find the variance and standard deviation.

Short Answer

Expert verified
In the given statistics class, we expect 30 students to pass the course, with a variance of 7.5 and a standard deviation of approximately 2.74 students.

Step by step solution

01

Calculate the expected number of students who will pass

Using the formula for the expected value of a binomial distribution: Expected value (mean) = n * p = 40 students * 0.75 probability of passing = 30 students The expected number of students who will pass the course is 30.
02

Calculate the variance

Next, we use the formula for the variance of a binomial distribution: Variance = n * p * (1-p) = 40 students * 0.75 probability of passing * 0.25 probability of failing = 7.5 The variance is 7.5.
03

Calculate the standard deviation

Finally, we use the formula for the standard deviation, which is the square root of the variance: Standard deviation = sqrt(variance) = sqrt(7.5) ≈ 2.74 The standard deviation is approximately 2.74 students. In conclusion, we expect 30 students to pass the course, with a variance of 7.5, and a standard deviation of approximately 2.74 students.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Let \(\mathrm{X}\) and \(\mathrm{Y}\) be jointly distributed with density function $$ \begin{array}{rlrl} \mathrm{f}(\mathrm{x}, \mathrm{y})= & 1 & 0<\mathrm{x}<1 \\ & & 0<\mathrm{y}<1 \\ & 0 & & \text { otherwise. } \end{array} $$ $$ \text { Find } \quad F(\lambda \mid X>Y)=\operatorname{Pr}(X \leq \lambda \mid X>Y) \text { . } $$

A physchologist wishes to determine the variation in I.Q.s of the population in his city. He takes many random samples of size 64 . The standard error of the mean is found to be equal to \(2 .\) What is the population standard deviation?

Find the expected value of the random variable \(\mathrm{S}^{2}{*}=(1 / \mathrm{n})^{\mathrm{n}} \sum_{\mathrm{i}=1}\left(\mathrm{X}_{\mathrm{i}}-\underline{\mathrm{X}}\right)^{2}\), where \(\underline{\mathrm{X}}={ }^{\mathrm{n}} \sum_{\mathrm{i}=1} \mathrm{X}_{\mathrm{i}} / \mathrm{n}\) and the \(\mathrm{X}_{\mathrm{i}}\) are independent and identically distributed with \(\mathrm{E}\left(\mathrm{X}_{\mathrm{i}}\right)=\mu\), Var \(\mathrm{X}_{\mathrm{i}}=\sigma^{2}\) for \(\mathrm{i}=1,2 \ldots \ldots \mathrm{n}\)

Given that \(\mathrm{x}\) has a normal distribution with mean 10 and standard deviation 4, find \(\mathrm{P}(\mathrm{x}<15)\).

What size sample is required to establish a \(.95\) confidence interval for the grade point average of students attending Ponoma State Teachers College if a random sample of 100 students had a mean grade point average of \(2.8\) with a standard deviation of \(.4\) and if the length of the interval is .1?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free