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Find the variance of the sample of observations \(2,5,7,9,12\).

Short Answer

Expert verified
The variance of the sample of observations \(2, 5, 7, 9, 12\) is \(11.6\).

Step by step solution

01

Calculate the mean of the sample.

First, we need to find the mean of the sample. The mean is the average of all the observations. To find the mean, add all the observations and divide the sum by the number of observations. Mean = \(\frac{sum \ of \ observations}{number \ of \ observations}\) The sum of the observations: \(2 + 5 + 7 + 9 + 12 = 35\) Number of observations: \(5\) Mean = \(\frac{35}{5} = 7\)
02

Find the differences between each observation and the mean.

Now, we need to find the differences between each observation and the mean calculated in Step 1. Difference 1: \(2 - 7 = -5\) Difference 2: \(5 -7 = -2\) Difference 3: \(7- 7 = 0\) Difference 4: \(9 - 7 = 2\) Difference 5: \(12 - 7 = 5\)
03

Square the differences.

In this step, we need to square each of the differences found in Step 2. Squared Difference 1: \((-5)^2 = 25\) Squared Difference 2: \((-2)^2 = 4\) Squared Difference 3: \((0)^2 = 0\) Squared Difference 4: \((2)^2 = 4\) Squared Difference 5: \((5)^2 = 25\)
04

Find the mean of the squared differences.

To find the mean of the squared differences, add all the squared differences and divide the sum by the number of squared differences. Mean of Squared Differences = \(\frac{sum \ of \ squared \ differences}{number \ of \ squared \ differences}\) The sum of squared differences: \(25 + 4 + 0 + 4 + 25 = 58\) Number of squared differences: \(5\) Mean of Squared Differences = \(\frac{58}{5} = 11.6\)
05

The variance is the result obtained in step 4.

Finally, the variance of the sample of observations is the result obtained in step 4, which is 11.6. So, the variance of the sample of observations \(2,5,7,9,12\) is \(11.6\).

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Most popular questions from this chapter

A random sample of 20 boys and 15 girls were given a standardized test. The average grade of the boys was 78 with a standard deviation of 6, while the girls made an average grade of 84 with a standard deviation of 8 . Test the hypothesis that \(\sigma_{1}^{2}=\sigma_{2}^{2}\) against the alternate hypothesis \(\sigma_{1}^{2}<\sigma_{2}^{2}\) where \(\sigma_{1}^{2}\) and \(\sigma_{2}^{2}\) are the variances of the population of boys and girls. Use a .05 level of significance.

An experimenter compared two groups, an experimental group and a control group. Each group contained 10 subjects. Do the two means of these groups differ significantly? $$ \begin{array}{|c|c|} \hline \text { Control } & \text { Experimental } \\ \hline 10 & 7 \\ 5 & 3 \\ 6 & 5 \\ 7 & 7 \\ 10 & 8 \\ 6 & 4 \\ 7 & 5 \\ 8 & 6 \\ 6 & 3 \\ 5 & 2 \\ \hline \end{array} $$

Let \(\mathrm{Y}=\) the Rockwell hardness of a particular alloy of steel. Assume that \(\mathrm{Y}\) is a continuous random variable that can take on any value between 50 and 70 with equal probability. Find the expected Rockwell hardness.

Let \(\mathrm{T}\) be distributed with density function \(f(t)=\lambda e^{-\lambda . t} \quad\) for \(t>0\) and \(=0\) otherwise If \(S\) is a new random variable defined as \(S=\) In \(\mathrm{T}\), find the density function of \(\mathrm{S}\).

Suppose that you want to decide which of two equally-priced brands of light bulbs lasts longer. You choose a random sample of 100 bulbs of each brand and find that brand \(\mathrm{A}\) has sample mean of 1180 hours and sample standard deviation of 120 hours, and that brand \(\mathrm{B}\) has sample mean of 1160 hours and sample standard deviation of 40 hours. What decision should you make at the \(5 \%\) significance level?

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