Identify All Subsets:
Now, we want to find all possible subsets of \(\mathrm{A} \times \mathrm{B}\), which means finding all combinations of elements in our cartesian product. We start with an empty subset, then we build subsets with one element, two elements, and so on, until we reach the maximum number of elements, which is equal to the size of \(\mathrm{A} \times \mathrm{B}\). In this case, since \(\mathrm{A} \times \mathrm{B}\) contains 4 elements, we have:
- Empty subset: \(\emptyset\)
- Subsets with 1 pair: \(\{(4, 1)\}, \{(4, 2)\}, \{(9, 1)\}, \{(9, 2)\}\)
- Subsets with 2 pairs: \(\{(4, 1), (4, 2)\}, \{(4, 1), (9, 1)\}, \{(4, 1), (9, 2)\}, \{(4, 2), (9, 1)\}, \{(4, 2), (9, 2)\}, \{(9, 1), (9, 2)\}\)
- Subsets with 3 pairs: \(\{(4, 1), (4, 2), (9, 1)\},\{(4, 1), (4, 2), (9, 2)\},\{(4, 1), (9, 1), (9, 2)\},\{(4, 2), (9, 1), (9, 2)\}\)
- Subsets with 4 pairs: \(\{(4, 1), (4, 2), (9, 1), (9, 2)\}\)
So all subsets of \(\mathrm{A} \times \mathrm{B}\) are as follows:
$$\{\emptyset, \{(4, 1)\}, \{(4, 2)\}, \{(9, 1)\}, \{(9, 2)\}, \{(4, 1), (4, 2)\}, \{(4, 1), (9, 1)\}, \{(4, 1), (9, 2)\}, \{(4, 2), (9, 1)\}, \{(4, 2), (9, 2)\}, \{(9, 1), (9, 2)\}, \{(4, 1), (4, 2), (9, 1)\}, \{(4, 1), (4, 2), (9, 2)\}, \{(4, 1), (9, 1), (9, 2)\}, \{(4, 2), (9, 1), (9, 2)\}, \{(4, 1), (4, 2), (9, 1), (9, 2)\}\}$$