Question

To find a dot product between \({\rm{a}}\) and \({\rm{b}}\).

Short answer

The dot product \(a \cdot b\) is \( - 1\)

Step-by-step solution

Concept of the Dot Product

The minimum of two vectors are required to perform a dot product. The resultant dot product of two vectors is scalar. hence, the dot product is also known as a scalar product.

Calculation of the dot product

The given two vectors are\({\rm{a}} = \langle 6, - 2,3\rangle \) and \({\rm{b}} = \langle 2,5, - 1\rangle \)

Consider a general expression to find the dot product between two three-dimensional vectors.

\(\begin{aligned}{l}{\rm{a}} \cdot {\rm{b}} &= \left\langle {{a_1},{a_2},{a_3}} \right\rangle \cdot \left\langle {{b_1},{b_2},{b_3}} \right\rangle \\{\rm{a}} \cdot {\rm{b}} &= {a_1}{b_1} + {a_2}{b_2} + {a_3}{b_3}\end{aligned}\)

Substitute\(6\)for \({a_1}, - 2\) for \({a_2},3\) for \({a_3},2\) for \({b_1},5\) for \({b_2}\), and \( - 1\) for \({b_3}\).

\(\begin{aligned}{l}a \cdot b &= (6)(2) + ( - 2)(5) + (3)( - 1)\\a \cdot b &= 12 - 10 - 3\\a \cdot b &= - 1\end{aligned}\)

Thus, \(a \cdot b\)is \( - 1\).