Question

Find the magnitude of the torque about \({\rm{P}}\)if a \({\rm{50 - N}}\)force is applied as shown.

Short answer

The magnitude of the torque is\({\rm{1000}}\sqrt {\rm{3}} {\rm{Ncm}}\).

Step-by-step solution

To calculate torque, use the following formula.

\({\rm{|\tau | = |r||F|sin\theta }}\)

The radius is\({\rm{40\;cm}}\), the angle between the position and the force is\({\rm{9}}{{\rm{0}}^{\rm{^\circ }}}\), the force is\({\rm{50\;N}}\), and the angle between the position and the force is\({\rm{9}}{{\rm{0}}^{\rm{^\circ }}}\).

\(\begin{aligned}{l}{\rm{|\tau | = (40)(50)sin60}}\\{\rm{ = }}\frac{{{\rm{2000}}\sqrt {\rm{3}} }}{{\rm{2}}}\\{\rm{ = 1000}}\sqrt {\rm{3}} \end{aligned}\)

Result.

\({\rm{|\tau | = 1000}}\sqrt {\rm{3}} {\rm{Ncm}}\)

Therefore, the magnitude of the torque is\({\rm{1000}}\sqrt {\rm{3}} {\rm{Ncm}}\).