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Describe the representation of inequality \({x^2} + {y^2} + {z^2} \le 3\) in \({R^3}\).

Short Answer

Expert verified

The inequality \({x^2} + {y^2} + {z^2} \le 3\) in \({R^3}\) represents a region in which all points lie on or inside the sphere with radius \(\sqrt 3 \) and center is at the origin \((0,0,0)\).

Step by step solution

01

Concept of Sphere.

The equation of a sphere with center\(C(h,k,l)\)and radius\(r\)is\({(x - h)^2} + {(y - k)^2} + {(z - l)^2} = {r^2}\).

02

Simplify the inequality into equation \({x^2} + {y^2} + {z^2} = 3\).

The given inequality in \({R^3}\) is \({x^2} + {y^2} + {z^2} \le 3\).

The equation can be rewrite as \({(x - 0)^2} + {(y - 0)^2} + {(z - 0)^2} = {(\sqrt 3 )^2}.\)

The equation is similar to the standard equation of a sphere with center \((0,0,0)\) and radius \(r = \sqrt 3 \).

The equation \({x^2} + {y^2} + {z^2} = 3\) in \({R^3}\) represents the region in which all points lie on the sphere with radius \(\sqrt 3 \) and center is at the origin \((0,0,0)\).

The equation \({x^2} + {y^2} + {z^2} = 3\) in \({R^3}\) represents the region in which all points lie inside the sphere with radius \(\sqrt 3 \) and center is at the origin \((0,0,0)\).

Thus, the inequality \({x^2} + {y^2} + {z^2} \le 3\) in \({R^3}\) represents a region in which all points lie on or inside the sphere with radius \(\sqrt 3 \) and center is at the origin \((0,0,0)\).

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