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Find whether the line through the points \(( - 4, - 6,1)\) and \(( - 2,0, - 3)\) is parallel to the line through the points \((10,18,4)\) and \((5,3,14)\) or not.

Short Answer

Expert verified

The line through the points \(( - 4, - 6,1)\) and \(( - 2,0, - 3)\) is parallel to the line through the points \((10,18,4)\) and \((5,3,14)\).

Step by step solution

01

Write the expression to find direction vector.

Formula used

\({\rm{v}} = \left\langle {\left( {{x_2} - {x_1}} \right),\left( {{y_2} - {y_1}} \right),\left( {{z_2} - {z_1}} \right)} \right\rangle (1)\)

02

Calculate the direction vector \((v)\). 

In equation (1), \( - 4\) for \({x_1}, - 6\) for \({y_1},1\) for \({z_1}, - 2\) for \({x_2},0\) for \({y_2}\), and \( - 3\) for \({z_2}\).

\(\begin{array}{l}{{\rm{v}}_1} = \langle ( - 2 - ( - 4)),(0 - ( - 6)),( - 3 - 1)\rangle \\{{\rm{v}}_1} = \langle 2,6, - 4\rangle \end{array}\)

In equation (1), 10 for \({x_1},18\) for \({y_1},4\) for \({z_1},5\) for \({x_2},3\) for \({y_2}\), and 14 for \({z_2}\).

\(\begin{array}{l}{v_2} = \langle (5 - 10),(3 - 18),(14 - 4)\rangle \\{v_2} = \langle - 5, - 15,10\rangle \end{array}\)

The direction vector \({v_2}\) is also written as.

\(\begin{array}{l}{{\rm{v}}_2} = \left( { - \frac{5}{2}} \right)\langle 2,6, - 4\rangle \\{{\rm{v}}_2} = \left( { - \frac{5}{2}} \right){{\rm{v}}_1}\end{array}\)

As the direction vector of line through the points \((10,18,4)\) and \((5,3,14)\) is multiple of the direction vector of line through the points \(( - 4, - 6,1)\) and \(( - 2,0, - 3)\), the two lines are in parallel.

Thus, the line through the points \(( - 4, - 6,1)\) and \(( - 2,0, - 3)\) is parallel to the line through the points \((10,18,4)\) and \((5,3,14)\).

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