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Determine whether the statement is true or false. If it is true, explainWhy. If it is false, explain why or give an example that disproves theStatement.

There is a vector field \({\rm{F}}\) such that curl

\({\rm{F = xi + yj + zk}}\)

Short Answer

Expert verified

The vector field \(G\)does not exist.

FALSE

Step by step solution

01

The property is satisfied by every vector function.

\({\rm{div(curlG) = 0}}\)

02

 If a vector field \({\rm{G}}\)exists, then the divergence of curl \({\rm{G}}\)must be \({\rm{0}}\) for all  \(x,y\)and \(z\)values.

\begin{aligned}curlG &= xi + yj + zk \\ div(curlG) &= div(xi + yj + zk) \\ div(curlG) &= \frac{{\partial (x)}}{{\partial x}} + \frac{{\partial (y)}}{{\partial y}} + \frac{{\partial (z)}}{{\partial z}} \\ div(curlG) &= 1 + 1 + 1 = 3 \\ \end{aligned}

As a result, there is no such vector field as G

FALSE

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