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Determine whether the geometric series is convergent or divergent..If it is convergent,find its sum.

\(\sum\limits_{n = 1}^\infty {\frac{{{{(10)}^n}}}{{{{( - 9)}^{n - 1}}}}} \)

Short Answer

Expert verified

The given series is Divergent..\(\)

Step by step solution

01

Finding the common ratio

Given Series\(\sum\limits_{n = 1}^\infty {\frac{{{{(10)}^n}}}{{{{( - 9)}^{n - 1}}}}} = 10 - \frac{{100}}{9} + \frac{{1000}}{{81}} - \frac{{10000}}{{243}} + .....\)

Common Ratio of this series=\(\frac{{{a_{n + 1}}}}{{{a_n}}}\)=\(\frac{{ - 100}}{9}*\frac{1}{{10}} = - \frac{{10}}{9}\)

02

Checking convergent /Divergent

Since,\(|r| = \frac{{10}}{9} > 1\)

Hence,The Series is Divergent…

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