Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

The Vander Waals equation for n moles of a gas is \(\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\left( {V - nb} \right) = nRT\) where P is the pressure, V is volume and T is the temperature of the gas. The constant R is the universal gas constant and \(a\) and \(b\)are positive constants that are characteristics of a particular gas. Calculate \(\frac{{\partial T}}{{\partial P}}\)and \(\frac{{\partial P}}{{\partial V}}\).

Short Answer

Expert verified

A partial differential equation (PDE) is a mathematical equation that establishes relationship between the partial derivatives of a multivariable function.

Step by step solution

01

Given data

Given: \(\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\left( {V - nb} \right) = nRT\)

Where P\( \to \)Pressure

V\( \to \)Volume

T\( \to \)Temperature

R\( \to \)Gas constant

a, b\( \to \)Positive constant

02

Differentiate with respect to T

\(\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\left( {V - nb} \right) = nRT\)

\(T = \frac{{\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\left( {V - nb} \right)}}{{nR}}\)

\(\frac{{\partial T}}{{\partial P}} = \frac{{V - nb}}{{nR}}\frac{\partial }{{\partial P}}\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\)

\(\frac{{\partial T}}{{\partial P}} = \frac{{V - nb}}{{nR}}\)

03

Differentiate with respect to V.

\(\left( {P + \frac{{{n^2}a}}{{{V^2}}}} \right)\left( {V - nb} \right) = nRT\)

\(P + \frac{{a{n^2}}}{{{V^2}}} = \frac{{nRT}}{{V - nb}}\)

\(\frac{{\partial P}}{{\partial V}} = - \frac{{nRT}}{{{{(V - nb)}^2}}} + \frac{{2{n^2}a}}{{{V^2}}}\)

Therefore,\(\frac{{\partial T}}{{\partial P}} = \frac{{V - nb}}{{nR}}\)

\(\frac{{\partial P}}{{\partial V}} = - \frac{{nRT}}{{{{(V - nb)}^2}}} + \frac{{2{n^2}a}}{{{V^2}}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free