Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Estimate the rate of change of the speed of sound\(C = 1449.2 + 4.6T - 0.055{T^2} + 0.00029{T^3} + 0.016D\) experienced by the driver 20 minutes into the dive and define its unit.

Short Answer

Expert verified

The speed of sound experienced by the driver decreasing approximately\(0.32(\;{\rm{m}}/{\rm{s}})/{\rm{min}}\).

Step by step solution

01

Chain rule

"Suppose that\(z = f(x,y)\)is a differentiable function of\(x\)and\(y\), where\(x = g(t)\)and\(y = h(t)\)are both differentiable functions of\(t\). Then,\(z\)is differentiable function of\(t\)and\(\frac{{dz}}{{dt}} = \frac{{dz}}{{dx}} \cdot \frac{{dx}}{{dt}} + \frac{{dz}}{{dy}} \cdot \frac{{dy}}{{dt}}\)”

02

Step 2: Estimate the rate of change of the speed of sound

As given, the speed of sound is, \(C = 1449.2 + 4.6T - 0.055{T^2} + 0.00029{T^3} + 0.016D\)

Where, \(T\) is temperature in degree Celsius. \(D\) is depth below the ocean surface in meters.

Apply chain rule case 1

\(\begin{aligned}{l}\frac{{dC}}{{dt}} = \frac{{\partial C}}{{\partial T}}\frac{{dT}}{{dt}} + \frac{{\partial C}}{{\partial D}}\frac{{dD}}{{dt}}\\\frac{{dC}}{{dt}} = \left( {4.6 - 0.11T + 0.00087{T^2}} \right) \cdot {T_t} + 0.016 \cdot {D_t}\end{aligned}\)

At the instant \(t = 20\),

\(\frac{{dC}}{{dt}}(20) = \left( {4.6 - 0.11 \cdot T(20) + 0.00087 \cdot T{{(20)}^2}} \right) \cdot {T_t}(20) + 0.016 \cdot {D_t}(20)\)

By using the given information on the graphics of the functions \(T(t)\) and \(D(t)\), estimate \({T_t}(20)\) and \({D_t}(20)\) as follows,

\(\begin{aligned}{l}\frac{{dT}}{{dt}}(20) \approx \frac{{T(25) - T(20)}}{{25 - 20}}\\\frac{{dT}}{{dt}}(20) = \frac{{12 - 12.5}}{5}\\\frac{{dT}}{{dt}}(20) = - 0.1,\\\frac{{dD}}{{dt}}(20) \approx \frac{{D(25) - D(20)}}{{24 - 20}}\\\frac{{dD}}{{dt}}(20) = \frac{{10 - 7}}{4}\\\frac{{dD}}{{dt}}(20) = 0.75.\end{aligned}\)

Calculate \({C_t}(20)\)

\(\begin{aligned}{l}\frac{{dC}}{{dt}}(20) = \left( {4.6 - 0.11 \cdot T(20) + 0.00087 \cdot T{{(20)}^2}} \right) \cdot {T_t}(20) + 0.016 \cdot {D_t}(20)\\\frac{{dC}}{{dt}}(20) = - 0.324\end{aligned}\)

Thus, the speed of sound experienced by the driver decreasing approximately\(0.324(\;{\rm{m}}/{\rm{s}})/{\rm{min}}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free