Chapter 11: Q18E (page 623)
Sketch the graph of the function \(f\left( {x,y} \right) = 1 + 2{x^2} + 2{y^2}\)
Short Answer
The graph of the function \(f\left( {x,y} \right) = 1 + 2{x^2} + 2{y^2}\)
Chapter 11: Q18E (page 623)
Sketch the graph of the function \(f\left( {x,y} \right) = 1 + 2{x^2} + 2{y^2}\)
The graph of the function \(f\left( {x,y} \right) = 1 + 2{x^2} + 2{y^2}\)
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Get started for freeUse polar coordinates to find the limit. If \((r,\theta )\) are polar coordinates of the point \((x, y)\) with \(r \ge 0\) note that \(r \to {0^ + }\) as \((x,y) \to (0,0)\)
\(\mathop {lim}\limits_{(x,y) \to (0,0)} \left( {\frac{{{x^3} + {y^3}}}{{{x^2} + {y^2}}}} \right)\)
Equation 6 is a formula for the derivative \(\frac{{dy}}{{dx}}\) of a function defined implicitly by an equation \(F(x,y) = 0\), provided that \(F\) is differentiable and \({F_y} \ne 0\). Prove that if \(F\) has continuous second derivatives, then a formula for the second derivative of \(y\) is
\(\frac{{{d^2}y}}{{d{x^2}}} = - \frac{{{F_{xx}}F_y^2 - 2{F_{xy}}{F_s}{F_y} + {F_{yy}}F_x^2}}{{F_y^3}}\)
Find the limit, if it exists, or show that the limit does not exist.
\(\mathop {lim}\limits_{\left( {x,y} \right) \to \left( {0,0} \right)} \frac{{{x^2}y{e^y}}}{{{x^4} + 4{y^2}}}\)
Draw a tree diagram of the partial derivatives of the function. The functions are\(t = f(u,v,w)\), where\(u = u(p,q,r,s),v = v(p,q,r,s),w = w(p,q,r,s).\)
Find the limit, if it exists, or show that the limit does not exist.
\(\mathop {lim}\limits_{\left( {x,y} \right) \to \left( {1,2} \right)} \left( {5{x^3} - {x^2}{y^2}} \right)\)
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