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Given that is a differentiable function with \(f(2,5) = 6\),\({f_x}(2,5) = 1\) and \({f_y}(2,5) = - 1\),use a linear approximation to estimate \(f(2.2,4.9)\)..

Short Answer

Expert verified

The Value of \(f(2.2,4.9) = 6.3\)..

Step by step solution

01

Step-1(Equation used in finding the Linear Approximation )

The equation use to find Approximation is:-

\(L(x,y) = f(a,b) + {f_x}(a,b)(x - a) + {f_y}(a,b)(y - b)\),where \({f_x}\)and\({f_y}\) are partial derivatives..

02

Step-2(Calculation of Approximation)

\(L(x,y) = f(a,b) + {f_x}(a,b)(x - a) + {f_y}(a,b)(y - b)\)

\(L(x,y) = 6 + 1(x - 2) - 1(y - 5)\)

\(L(x,y) = x - y + 9\)

\(\)To evaluate the value \(f(2.2,4.9)\)substitute \(x = 2.2\)and \(y = 4.9\)

\(L(x,y) = x - y + 9\)

\(f(2.2,4.9)\)=\(L(2.2,4.9)\)

\( = 2.2 - 4.9 + 9\)

\( = 6.3\)

Hence,the value of \(f(2.2,4.9) = 6.3\)..

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