Chapter 9: Q13RE (page 535)
Sketch the polar curve.
\({\rm{r = 1 + cos2\theta }}\)
Short Answer
The polar curve \({\rm{r = 1 + cos2\theta }}\) is symmetric about both the x and y axes, as can be seen in Figure 1.
Chapter 9: Q13RE (page 535)
Sketch the polar curve.
\({\rm{r = 1 + cos2\theta }}\)
The polar curve \({\rm{r = 1 + cos2\theta }}\) is symmetric about both the x and y axes, as can be seen in Figure 1.
All the tools & learning materials you need for study success - in one app.
Get started for freePlot the point whose polar coordinates are given. Then find the Cartesian coordinates of the point.
\(\begin{aligned}{l}(a)(1,\pi )\\(b)(2, - 2\pi /3)\\(c)( - 2,3\pi /4)\end{aligned}\)
Sketch the curve with the given polar equation by first sketching the graph\({\rm{r}}\) as a function of\({\rm{\theta }}\) Cartesian coordinates.
\({\rm{r = 2cos4\theta }}\)
Show that the curve \({\rm{r = sin\theta tan\theta }}\) (called a cissoid of Diocles) has the line \({\rm{x = 1}}\)as a vertical asymptote. Show also that the curve lies entirely within the vertical strip \({\rm{0}} \le {\rm{x < 1}}{\rm{.}}\)Use these facts to help sketch the cissoids.
Sketch the curve with the given polar equation by first sketching the graph\({\rm{r}}\)as a function of\({\rm{\theta }}\)Cartesian coordinates.
To determine
a) To match the polar equation \(r = \sqrt \theta ,0 \le \theta \le 16\pi \) with the given graphs labeled as \({\rm{I}} - {\rm{VI}}\).
b) To match: The polar equation \(r = {\theta ^2}\) with the given graphs labeled as \({\rm{I}} - {\rm{VI}}\).
c) To match the polar equation \(r = 1 + 2\cos \theta \) with the given graphs labeled as \({\rm{I}} - {\rm{VI}}\).
d) To match the polar equation \(r = 2 + \sin 3\theta \) with the given graphs labeled as \({\rm{I}} - {\rm{VI}}\).
e) To match: The polar equation \(r = 1 + 2\sin 3\theta \) with the given graphs labeled as \({\rm{I}} - {\rm{VI}}\).
What do you think about this solution?
We value your feedback to improve our textbook solutions.