Chapter 12: Q7E (page 728)
To evaluate the integral of .
Short Answer
The value of the given iterated integral is \(\frac{{27}}{2}\).
Chapter 12: Q7E (page 728)
To evaluate the integral of .
The value of the given iterated integral is \(\frac{{27}}{2}\).
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Get started for freeFind the volume of the solid that is enclosed by the cone \({\rm{z = }}\sqrt {{{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}} \) and the sphere \({{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}{\rm{ + }}{{\rm{z}}^{\rm{2}}}{\rm{ = 2}}\).Use cylindrical coordinates.
Set up, but do not evaluate, integral expressions for
The hemisphere.
Let \({\rm{E}}\) be the solid in the first octant bounded by the cylinder \({{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}{\rm{ = 1}}\) and the planes \({\rm{y = z, x = 0}}\)and \({\rm{z = 0}}\)with the density function \({\rm{\rho (x,y,z) = 1 + x + y + z}}\). Use a computer algebra system to find the exact values of the following quantities for \({\rm{E}}\).
\(\int\limits_{ - 2}^2 {\int\limits_0^{\sqrt {4 - {y^2}} } {f(x,y)dy} dx} \)
Sketch the solid whose volume is given by the integrated integral.
\(\int\limits_0^1 {\int\limits_0^1 {\left( {2 - {x^2} - {y^2}} \right)dydx} } \)
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