Chapter 12: Q7E (page 734)
To determine the surface of the equation \(z = 4 - {r^2}\).
Short Answer
The surface of \(z = 4 - {r^2}\) is a circular paraboloid.
Chapter 12: Q7E (page 734)
To determine the surface of the equation \(z = 4 - {r^2}\).
The surface of \(z = 4 - {r^2}\) is a circular paraboloid.
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Get started for freeEvaluate the iterated integral \(\int\limits_0^1 {\int\limits_{2x}^2 {(x - y)dxdy} } \)
\(\int {\int\limits_D y dA} \).
Find the volume of the solid that lies between the paraboloid \({\rm{z = }}{{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}\)and the sphere \({{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}{\rm{ + }}{{\rm{z}}^{\rm{2}}}{\rm{ = 2}}\).
Describe in words the surface whose equation is given
\({\rm{r = 5}}\).
Use symmetry to evaluate the double integral
\(R = ( - \pi ,\pi ) \times ( - \pi ,\pi )\)
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