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Evaluate the iterated integral \(\int_0^2 {\int_y^{2y} x } ydxdy\)

Short Answer

Expert verified

Value of integral is \(6\).\(\)

Step by step solution

01

Integrating with respect to \(x\).

\(\int_0^2 {\int_y^{2y} x } ydxdy = \int_0^2 y \left( {\frac{{{x^2}}}{2}} \right)_y^{2y}dy\)

\( = \frac{1}{2}\int_0^2 y \left( {4{y^2} - {y^2}} \right)dy\)

\( = \frac{3}{2}\int_2^3 {\left( {{y^3}} \right)} dy\)

\( = \frac{3}{2}\left( {\frac{{{y^4}}}{4}} \right)_0^2\)

\( = \frac{3}{2}\left( {\frac{{16}}{4} - 0} \right)\)

\( = 6\)

Hence, The value is \(6\).

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