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To evaluate the integral of by arranging different orders of integration.

Short Answer

Expert verified

The value of the given integral is \(21\)

Step by step solution

01

The given function and region is

The function is \(f(x,y,z) = xy + {z^2}\).

The region is \(E = \{ (x,y,z)\mid 0 \le x \le 2,0 \le y \le 1,0 \le z \le 3\} \).

02

Case 1, where order of integration is \(x\), \(y\) and \(z\)

The given integral with the above order is .

Integrate the given integral with respect to \(x\) and apply the limit of it.

Integrate the given integral with respect to \(y\) and apply the limit of it.

Integrate the given integral with respect to \(z\) and apply the limit of it.

Simplify further to obtain the value.

Thus, the value of the integral with the order \(x\), \(y\) and \(z\) is 21 .

03

Case 2, where order of integration proceed with the order \(y\), then \(z\) and \(x\)

The given integral with the above order is .

Integrate the given integral with respect to \(y\) and apply the limit of it.

Integrate the given integral with respect to \(z\) and apply the limit of it.

Integrate the given integral with respect to \(x\) and apply the limit of it.

Thus, the value of the integral with the order \(y\), \(z\) and \(x\) is 21 .

04

Case 3, where order of integration proceed with the order \(z\), then \(x\) and \(y\)

The given integral with the above order is .

Integrate the given integral with respect to \(z\) and apply the limit of it.

Integrate the given integral with respect to \(x\) and apply the limit of it.

Integrate the given integral with respect to \(y\) and apply the limit of it.

Thus, the value of the integral with the order \(z\), \(x\) and \(y\) is 21 .

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