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Describe in words the surface whose equation is given\({\rm{\rho = 3}}\).

Short Answer

Expert verified

The surface of the given equation is the sphere of radius \({\rm{3}}\) centered at the origin.

Step by step solution

01

Given data.

\({\rm{\rho = 3}}\)

02

Surface of the equation.

Spherical coordinates,

\(\begin{array}{l}{\rm{(1)x = \rho sin}}\phi {\rm{cos\theta }}\\{\rm{(2)y = \rho sin}}\phi {\rm{sin\theta }}\\{\rm{(3)z = \rho cos}}\phi \\{\rm{(4)}}{{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}{\rm{ + }}{{\rm{z}}^{\rm{2}}}{\rm{ = }}{{\rm{\rho }}^{\rm{2}}}\end{array}\)

Spherical coordinates are \({{\rm{x}}^{\rm{2}}}{\rm{ + }}{{\rm{y}}^{\rm{2}}}{\rm{ + }}{{\rm{z}}^{\rm{2}}}{\rm{ = }}{{\rm{\rho }}^{\rm{2}}}\). If the value \({\rm{\rho }}\) is fixed, this is also the equation of a sphere. As a result, the equation's surface is a sphere of radius \({\rm{3}}\) centered at the origin.

Therefore, the surface of the equation is a sphere of radius \({\rm{3}}\) centered at the origin.

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