Chapter 3: Q9E (page 161)
Determine whether the function\(f(x) = {x^2} - 2x\)is one-to-one.
Short Answer
The function \(f(x) = {x^2} - 2x\) is not a one-to-one.
Chapter 3: Q9E (page 161)
Determine whether the function\(f(x) = {x^2} - 2x\)is one-to-one.
The function \(f(x) = {x^2} - 2x\) is not a one-to-one.
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Get started for free(a) Determine the inverse function \({f^{ - 1}}\). What is the domain and range of \({f^{ - 1}}\).
(b) Determine the formula for \({f^{ - 1}}\) if the formula for \(f\) is given.
(c) How to obtain the graph of \({f^{ - 1}}\) if the graph of \(f\) is given \(f\).
1โ38 โ Find the limit. Use lโHospitalโs Rule where appropriate. If there is a more elementary method, consider using it. If lโHospitalโs Rule doesnโt apply, explain why.
10.\(\mathop {lim}\limits_{x \to \infty } \frac{{ln\sqrt x }}{{{x^2}}}\).
Determine whether the function \(f\left( t \right)\) which reflects a personโs height at age\(t\) is one-to-one or not.
To determine the value of \(\mathop {\lim }\limits_{x \to {2^ + }} \left( {{e^{\frac{3}{{2 - x}}}}} \right)\).
To determine the value of \(\mathop {\lim }\limits_{x \to {{\left( {\frac{\pi }{2}} \right)}^ + }} \left( {{e^{\tan x}}} \right).\)
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