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Find the exponential function which is of the form \(f(x) = C{b^x}\) for the given graph.

Short Answer

Expert verified

The equation of the graph is \(f(x) = 3{(2)^x}\).

Step by step solution

01

Given data

The equation of the given graph is of the form \(f(x) = C{b^x}\).

02

Concept of the domain of an exponential function

The domain is the set of all input values of the function for which the function is real and defined.

The domain of an exponential functions\(y = {a^x},\;a > 0\)and\(a \ne 1\)is the set of real values.

That is,\( - \infty < x < \infty \).

03

Find the value of \(b\)

Here, the graph represents a curve which passes through the points \((3,24)\) and \((1,6)\).

Substitute these points in \(f(x) = C{b^x}\).

\(24 = C{b^3}\) ……. (1)

\(6 = C{b^1}\) ……. (2)

Divide the equation (1) by equation (2) and obtain the value of \(b\) as follows:

\(\begin{array}{c}\frac{{24}}{6} = \frac{{C{b^3}}}{{C{b^1}}}\\4 = {b^2}\\b = \pm 2\end{array}\)

Ignore the negative value of \(b\) as it cannot take the negative values.

Thus, the value of \(b = 2\).

04

Find the value of \(C\)

Substitute \(b = 2\) in equation (1) and obtain the value of \(C\) as shown below.

\(\begin{array}{c}24 = C{2^3}\\24 = 8C\\C = 3\end{array}\)

Therefore, the value of \(C = 3\).

05

Find the exponential function

Substitute the value of \(b\) and \(C\) in \(f(x) = C{b^x}\) and obtain the required equation as given below.

\(\begin{array}{l}f(x) = C{b^x}\\f(x) = 3{(2)^x}\end{array}\)

Therefore, equation of the exponential function which passes through the points \((3,24)\) and \((1,6)\)is \(f(x) = 3{(2)^x}\).

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