Chapter 3: Q12E (page 161)
Determine whether the function\(g(x) = \cos {\kern 1pt} {\kern 1pt} x\)is one-to-one.
Short Answer
The function \(g(x) = \cos {\kern 1pt} {\kern 1pt} x\) is not one-to-one.
Chapter 3: Q12E (page 161)
Determine whether the function\(g(x) = \cos {\kern 1pt} {\kern 1pt} x\)is one-to-one.
The function \(g(x) = \cos {\kern 1pt} {\kern 1pt} x\) is not one-to-one.
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Get started for free1โ38 โ Find the limit. Use lโHospitalโs Rule where appropriate. If there is a more elementary method, consider using it. If lโHospitalโs Rule doesnโt apply, explain why.
3.\(\mathop {lim}\limits_{x \to {{\left( {\frac{\pi }{2}} \right)}^ + }} \frac{{cosx}}{{1 - sinx}}\).
Determine the value of \({G^\prime }(2)\).
Prove the identity\(\frac{{{1 + tanhx}}}{{{1 - tanhx}}}{ = }{{e}^{{2x}}}\).
(a) To show any function of the form \(y = Asinhmx + Bcoshmx\) satisfies the differential equation\({y^{\prime \prime }} = {m^2}y\).
(b) To determine the function \(y = y(x)\).
Sketch the graphs of the function \(y = {2^x},y = {e^x},y = {5^x}\) and \(y = {20^x}\) on the same axes and interpret how these graphs are related.
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