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If \(f\) is continuous and \(\int_0^4 f (x)dx = 10\), find \(\int_0^2 f (2x)dx\).

Short Answer

Expert verified

The value of the integral is: \(\int\limits_0^2 {f(2x)dx = 5} \)

Step by step solution

01

Step 1: Given Information

If\(f(x)\)is a function defined on an interval\((a,b)\), the definite integral of\(f\)from\(a\)to\(b\)is given by

\(\int_a^b f (x)dx = \mathop {\lim }\limits_{n \to \infty i = 1}^n f\left( {x_i^*} \right)x{\rm{, }}\)

provided the limit exists. If this limit exists, the function \(f(x)\)is said to be integrable on \((a,b)\), or is an integrable function.

02

To find the value of Function

To Find the function

\(\int\limits_0^2 {f(2x)dx} \)

Substitute \(u = 2x\) into the expression:

\(\int\limits_0^2 {f(u)dx} \)

To find the value of the integral, first determine \(du\)by finding the derivative of \(du = {(2x)^'}\)

03

Step 3: calculate the right-side equation

Calculate the derivation of the right side of the equation:

\(du = 2dx\)

Divide both sides of the equation by\(2\):

\(\frac{{du}}{2} = \frac{{2dx}}{2}\)

\(\frac{{du}}{2} = \frac{{\cancel{2}dx}}{{\cancel{2}}}\)

Reduce the fraction:

\(\frac{{du}}{2} = dx\)

Swap the sides of the equation:

\(dx = \frac{{du}}{2}\)

Since the lower limit of the integral is\(0\)and\(u = 2x\), it follows that the lower limit of the new integral is:

\(u = 2 \times 0 = 0\)

Since the upper limit of the integral is\(2\)and\(u = 2x\), it follows that the lower limit of the new integral is:

\(u = 2 \times 2 = 4\)

\(\int\limits_0^2 {f(u)dx} \)

04

Step 4: Substitute the lower and upper Limit

Substitute lower limit with\(0\), upper limit with\(4\), and\(dx = \frac{{du}}{2}\)into the expression:

\(\int\limits_0^4 {f(u)\frac{{du}}{2}} \)

Rewrite the expression:

\(\int\limits_0^4 {\frac{1}{2}} f(u)du\)

05

Step 5: Final Proof

By using the constant property of integrals, it follows:

\(\frac{1}{2}\int\limits_0^4 {f(u)du} \)

Since\(\int\limits_0^4 {f(x)dx = 10} \), it follows:

\(\frac{1}{2} \times 10 = 5\)

Hence, the value of the integral is: \(\int\limits_0^2 {f(2x)dx = 5} \)

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