Chapter 1: Q22E (page 34)
(a) Evaluate \(h\left( x \right) = \frac{{\left( {\tan x - x} \right)}}{{{x^3}}}\)for \(x = {\bf{0}}.{\bf{5}},{\rm{ }}{\bf{0}}.{\bf{1}},{\rm{ }}{\bf{0}}.{\bf{05}},{\rm{ }}{\bf{0}}.{\bf{01}}\), and 0.005. (b) Guess the value of \(\mathop {\lim }\limits_{x \to 0} \frac{{\tan x - x}}{{{x^3}}}\).
(c) Evaluate \(h\left( x \right)\)for successively smaller values of xuntil you finally reach 0 values for \(h\left( x \right)\). Are you still confident that your guess in part (b) is correct? Explain why you eventually obtained 0 values. (In Section 3.7 a method for evaluating the limit will be explained.)
(d) Graph the function h in the viewing rectangle \(\left( { - 1,\;1} \right)\)by\(\left( {0,\;1} \right)\). Then zoom in toward the point where the graph crosses the y-axis to estimate the limit of \(h\left( x \right)\)as xapproaches 0. Continue to zoom in until you observe distortions in the graph of h. Compare with the results of part (c).
Short Answer
(a) The values of \(h\left( x \right)\) for the given values of \(x\)are\(0.557408\),\(0.370420\), \(0.334672\),\(0.333667\), \(0.333347\), and \(0.333337\).
(b) The values of \(\mathop {\lim }\limits_{x \to 0} \frac{{\tan x - x}}{{{x^3}}}\)is\(0.33\).
(c) The guess is not correct, and the explanation is given by the behavior of the numerator and the capability of the calculator as \(x\) approaches to zero.
(d) The graph of the function \(h\) is as follows.
The limit \(\mathop {\lim }\limits_{x \to 0} h\left( x \right)\) does not exist, and in the part (c), \(\mathop {\lim }\limits_{x \to 0} h\left( x \right) = 0\), and in this part the limit does not exist.