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Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example that disproves the statement.

4) If f is differentiable and\(f\left( { - 1} \right) = f\left( 1 \right)\), then there is a number c such that \(\left| c \right| < 1\) and \(f'\left( c \right) = 0\).

Short Answer

Expert verified

f is differentiable and \(f\left( { - 1} \right) = f\left( 1 \right)\), then there is a number c such that \(\left| c \right| < 1\) and \(f'\left( c \right) = 0\), is true using Rolle’s theorem.

Step by step solution

01

Given

Givenf is differentiable.

Such that,\(f\left( { - 1} \right) = f\left( 1 \right)\)

f is differentiable on

f is continuous on and

( given )

02

Apply Rolle’s theorem

Now by Rolle’s theorem,

\(\exists c \in \left( { - 1,1} \right)\)

Such that \(f'\left( c \right) = 0\)

Since \(c \in \left( { - 1,1} \right)\)

\(\therefore \left| c \right| < 1\)

And \(f'\left( c \right) = 0\) ( by above )

Hence our statement is true.

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