Question

Label any intercepts and sketch a graph of the plane. $$ 3 x+6 y+2 z=6 $$

Short answer

The intercepts are (2,0,0), (0,1,0) and (0,0,3). Connect these points to sketch the plane in the 3D Cartesian Coordinate system.

Step-by-step solution

Find the intercepts

To find the intercepts, set two variables to zero and solve for the remaining variable. Do this thrice to find all three intercepts.\n\nFor x-intercept, set y = 0, z = 0 in the given equation, which gives 3x = 6, so x = 2. \n\nFor y-intercept, set x = 0, z = 0 in the given equation, which gives 6y = 6, so y = 1. \n\nFor z-intercept, set x = 0, y = 0 in the given equation, which gives 2z = 6, so z = 3. \n\nTherefore, the intercepts are (2,0,0), (0,1,0) and (0,0,3).

Sketch the plane

Draw a 3D Cartesian Coordinate system. Now plot the points/intercepts (2,0,0), (0,1,0) and (0,0,3). To depict the plane, connect these three points. They create a triangle which lies on the plane. This is a basic representation of the plane.

Key concepts

3D Coordinate System

Understanding the 3D coordinate system is essential for graphing planes in calculus. Just as the 2D coordinate system consists of an x-axis and a y-axis, the 3D coordinate system introduces a third dimension called the z-axis.

This system can be visualized as a corner of a room where each axis represents a different dimension. The x-axis and y-axis lie on the floor creating a flat grid, while the z-axis runs upward, at right angles to both the x and y-axes. When plotting a point \( (x, y, z) \) in 3D, you move along the x-axis by \( x \) units, along the y-axis by \( y \) units, and then up or down along the z-axis by \( z \) units, depending on whether z is positive or negative.

Imagine this coordinate system like a scaffold in space, each axis representing potential directions in which you can move, and every point in the three-dimensional space can be marked by how far it lies along these three axes.

Intercepts of a Plane

When working with planes in a three-dimensional space, intercepts play a crucial role in understanding where the plane intersects with the coordinate axes. These intersections are known as the x-intercept, y-intercept, and z-intercept.

To find these intercepts, one at a time, set the other two variables to zero and solve for the remaining one. For instance, setting \( y = 0 \) and \( z = 0 \) yields the x-intercept, and similarly for the other two axes. In the given exercise, the intercepts found were \( (2,0,0) \) for the x-intercept, \( (0,1,0) \) for the y-intercept, and \( (0,0,3) \) for the z-intercept.

These intercepts are pivotal as they provide the specific points where the plane touches each axis, serving as crucial guides when sketching the plane in 3D space, and offering a clearer understanding of the plane's orientation and position relative to the origin.

Sketching Planes in Calculus

In calculus, sketching planes involves visualizing and drawing a flat surface that extends infinitely in all directions within three-dimensional space. Since it's challenging to represent an infinite plane on paper, we use the intercepts to sketch a representative portion of it.

After finding the plane's intercepts with the axes, these points are plotted within the 3D coordinate system. Then, lines are drawn to connect these points, forming a triangle, which is a segment of the plane. This triangle helps in visualizing the plane's position and slope. In the provided exercise solution, the intercepts formed a triangle by connecting \( (2,0,0) \) to \( (0,1,0) \) and \( (0,0,3) \) and then back to \( (2,0,0) \).

This graphical representation is useful for identifying properties such as the direction the plane is facing and how it intersects with other planes or lines in the space. Remember, the real plane is extensive and spreads out beyond the triangle formed; the triangle is simply a convenient way to illustrate part of the plane within our 3D graph.