Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Use a graphing utility to graph the equation and show that the given line is an asymptote of the graph. Conchoid $$ r=2-\sec \theta $$ $$ x=-1 $$

Short Answer

Expert verified
The Cartesian equation, obtained from the polar equation, can be graphed using a graphing tool. The vertical line \(x=-1\) identified in the graph respects the definition of an asymptote. Thus, \(x=-1\) is indeed an asymptote to the graph of the given polar equation \(r=2-\sec \theta\).

Step by step solution

01

Convert the Polar Equation to Cartesian Form

Given the polar equation \(r = 2 - \sec \theta\). Use the relationship between polar and Cartesian coordinates \(r = \sqrt{x^2+y^2}\) and \(\cos \theta = x/r\). Substitute these into the provided equation.
02

Simplify The Equation

After substitution, simplify the equation to obtain the Cartesian equation which will be helpful in graphing.
03

Graph the Equation and Identify the Asymptote

Utilize a graphing tool to graph the equation obtained above. An asymptote is a line that the curve gets closer to as it extends into infinity. Identify \(x=-1\) as this line in the graph.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free