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Sketch a graph of the polar equation and find the tangents at the pole. $$ r=2 \cos 3 \theta $$

Short Answer

Expert verified
The graph of the polar equation \( r = 2 \cos 3 \theta \) resembles a three-leaved flower. The tangents at the pole occur whenever the curve passes through the pole, that is, for the cases when \( \theta = \frac{\pi}{6}, \frac{\pi}{2}, \frac{5\pi}{6} \). Radiating lines from the origin to points where \( \theta \) has these values act as potential tangents.

Step by step solution

01

Graphing the Polar Equation

Plot different points by taking various values for \( \theta \) between 0 and \( \pi \) and then find the corresponding \( r \) using the given equation. Start with \( \theta = 0 \) and continue with small increments. Remember that in polar coordinates a point is expressed as (r, \( \theta \)), where \( r \) is the distance from the origin and \( \theta \) the angle from the positive x-axis. This should provide a clear graph of the given polar equation.
02

Identifying Pole Locations

The pole of a graph in polar coordinates is the origin of the coordinate system, where the value of \( r \) is zero. In this case, evaluate the equation \( r = 2 \cos 3 \theta \) to find for which values of \( \theta \), if any, \( r \) becomes zero.
03

Find the Tangents at the Pole

For those \( \theta \) values where \( r \) is zero, the curve passes through the pole. For such points, multiple tangents can be formed; with the pole being the origin, radiating lines (or rays) from the origin to points where \( \theta = \text{(constant)} \) function as potential tangents. These lines represent the different directions in which the curve leaves the pole.

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