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Write the first five terms of the sequence. \(a_{n}=10+\frac{2}{n}+\frac{6}{n^{2}}\)

Short Answer

Expert verified
The first five terms of the sequence are 18, 12.5, 11.22, 11.125, 11.08.

Step by step solution

01

Substitute n=1

Firstly, substitute n=1 into the formula \(a_{n}=10+\frac{2}{n}+\frac{6}{n^{2}}\). This will give \(a_{1}=10+\frac{2}{1}+\frac{6}{1^{2}}\), which simplifies to \(a_{1}=18\).
02

Substitute n=2

Secondly, substitute n=2 into the formula. It gives \(a_{2}=10+\frac{2}{2}+\frac{6}{2^{2}}\), which simplifies to \(a_{2}=12.5\).
03

Substitute n=3

Thirdly, substitute n=3 into the formula. It provides \(a_{3}=10+\frac{2}{3}+\frac{6}{3^{2}}\), which simplifies to roughly \(a_{3}=11.22\) (to two decimal places).
04

Substitute n=4

Fourthly, substitute n=4 into the formula, getting \(a_{4}=10+\frac{2}{4}+\frac{6}{4^{2}}\). Simplify it to \(a_{4}=11.125\).
05

Substitute n=5

Lastly, substitute n=5 into the formula. This makes \(a_{5}=10+\frac{2}{5}+\frac{6}{5^{2}}\), simplifying to roughly \(a_{5}=11.08\) (to two decimal places).

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Most popular questions from this chapter

Modeling Data The annual sales \(a_{n}\) (in millions of dollars) for Avon Products, Inc. from 1993 through 2002 are given below as ordered pairs of the form \(\left(n, a_{n}\right),\) where \(n\) represents the year, with \(n=3\) corresponding to 1993. (Source: 2002 Avon Products, Inc. Annual Report) (3,3844),(4,4267),(5,4492),(6,4814),(7,5079) (8,5213),(9,5289),(10,5682),(11,5958),(12,6171) (a) Use the regression capabilities of a graphing utility to find a model of the form \(a_{n}=b n+c, \quad n=3,4, \ldots, 12\) for the data. Graphically compare the points and the model. (b) Use the model to predict sales in the year 2008 .

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