Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(\sum_{n=1}^{\infty} a_{n}=L,\) then \(\sum_{n=0}^{\infty} a_{n}=L+a_{0}\).

Short Answer

Expert verified
The statement is true. By definition of an infinite series starting from n=0, the sum would naturally be the sum of the first term and the sum of the rest of the series.

Step by step solution

01

Understanding the problem

In the given statement, it's implied that adding the first term of the series (when n is 0), to the sum from n=1 to infinite, will give the sum from n=0 to infinite. This assertion seems logical, because adding a term to a sum would normally change the sum by that amount.
02

Evaluating the truthfulness

The given statement is actually true. If we have a series starting from n=0, then the first term will be given when n=0, i.e., \( a_{0} \), and rest of the series would be from n=1 to infinity, i.e., \( \sum_{n=1}^{\infty} a_{n} \). So, it's natural that the sum from n=0 to infinity, \( \sum_{n=0}^{\infty} a_{n} \), would be the sum of these, i.e., \( L+a_{0} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free