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Verify that the infinite series diverges. $$ \sum_{n=1}^{\infty} \frac{n^{2}}{n^{2}+1} $$

Short Answer

Expert verified
The given series \(\sum_{n=1}^{\infty} \frac{n^{2}}{n^{2}+1}\) diverges by the comparison test.

Step by step solution

01

Identify the Series to Compare

As \(n\) tends to infinity, the series \(\frac{n^{2}}{n^{2}+1}\) tends to \(1\). Therefore, we compare it to the series \(\sum_{n=1}^{\infty} 1\).
02

Apply Comparison Test for Divergence

The comparison test for divergence states that if every term of the series \(a_n\) is greater than or equal to the corresponding term in a diverging series \(b_n\), then the series \(a_n\) also diverges. Here, \(a_n = \frac{n^{2}}{n^{2}+1}\) and \(b_n = 1\). Since \(\frac{n^{2}}{n^{2}+1} \geq 1\) for \(n = 1\) and following, we can conclude that our series diverges.

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