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Write the first five terms of the recursively defined sequence. \(a_{1}=6, a_{k+1}=\frac{1}{3} a_{k}^{2}\)

Short Answer

Expert verified
The first five terms of the sequence are: 6, 12, 48, 768, 196,608.

Step by step solution

01

Identify the First Term

We can see that the first term is already given in the problem as \(a_{1}=6\). This will be the starting point for the sequence.
02

Compute the Second Term

The second term can be computed using the formula \(a_{k+1}=\frac{1}{3} a_{k}^{2}\). Plugging in \(k=1\) into the formula and using \(a_{1}=6\), we get \(a_{2}=\frac{1}{3} a_{1}^{2} = \frac{1}{3} * 6^2 = 12\).
03

Compute the Third Term

Similar to step 2, plug in \(k=2\) into the formula and use \(a_{2}=12\) to get \(a_{3}=\frac{1}{3} a_{2}^{2} = \frac{1}{3} * 12^2 = 48\).
04

Compute the Fourth Term

Repeat the process described in step 2 and 3. Plug in \(k=3\) into the formula and use \(a_{3}=48\). This yields \(a_{4}=\frac{1}{3} a_{3}^{2} = \frac{1}{3} * 48^2 = 768\).
05

Compute the Fifth Term

Similar to before, plug in \(k=4\) into the formula and use \(a_{4}=768\). This will get us the fifth term \(a_{5}=\frac{1}{3} a_{4}^{2} = \frac{1}{3} * 768^2 = 196,608\).

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