Chapter 6: Problem 76
Use integration by parts to verify the reduction formula. $$ \int \sec ^{n} x d x=\frac{1}{n-1} \sec ^{n-2} x \tan x+\frac{n-2}{n-1} \int \sec ^{n-2} x d x $$
Short Answer
Expert verified
The reduction formula of \(\int \sec ^{n} x dx = \frac{1}{n-1} \sec ^{n-2} x \tan x + \frac{n-2}{n-1} \int \sec ^{n-2} x dx\) can be verified using integration by parts.
Step by step solution
01
Apply the Integration by Parts Method
Firstly, select \(u = \sec^{n-2} x \) and \(dv = \sec ^2 x dx\). Integrate \(dv\) to get \(v = \tan x\), and differentiate \(u\) to get \(du = (n-2) \sec^{n-3} x \sec x \tan x dx = (n-2) \sec^{n-2} x \tan x dx\).
02
Use the Integration by Parts Formula
Next, plug \(u\), \(v\), \(du\), and \(dv\) into the integration by parts formula \(\int u dv = uv - \int v du\), which gives: \(\int \sec ^{n} x dx = \sec^{n-2} x \tan x - \int \tan x \cdot (n-2) \sec^{n-2} x \tan x dx.\) This can be simplified to: \(\int \sec^n x dx = \sec^{n-2} x \tan x - (n-2) \int \sec^{n-2} x \tan^2 x dx.\)
03
Replace the \(\tan ^2 x\) Part
Remember that \(\tan ^2 x = \sec ^2 x - 1\), replacing \(\tan ^2 x\) in the previous equation we obtain: \(\int \sec^n x dx = \sec^{n-2} x \tan x - (n-2) \int \sec^{n-2} x (\sec^2 x -1) dx\). Distribute to get: \(\int \sec^n x dx = \sec^{n-2} x \tan x - (n-2) \int \sec^n x dx + (n-2) \int \sec^{n-2} x dx.\)
04
Collect and Rearrange Terms
Move the equation \((n-2)\int \sec^n x dx\) from the right to the left side to get \((n-1) \int \sec^n x dx = \sec^{n-2} x \tan x + (n-2) \int \sec^{n-2} x dx\). Finally, divide by \((n-1)\) to get the reduction formula: \(\int \sec^n x dx = \frac{1}{n-1} \sec^{n-2} x \tan x + \frac{n-2}{n-1} \int \sec^{n-2} x dx\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Reduction Formula
The reduction formula is a powerful tool in integral calculus that simplifies the process of finding the integral of a function by reducing it to the integral of a lower power of that function. This is especially helpful when dealing with integrals of trigonometric functions where direct integration is complicated.
For example, in our exercise, the integral of \( \sec^n x \) is not straightforward as there is no simple antiderivative for this function. However, using the reduction formula, we express this integral in terms of the integral of \( \sec^{n-2} x \), which is of a lower power. Each application of the reduction formula decreases the exponent by two, progressively simplifying the integral until it can be solved.
For example, in our exercise, the integral of \( \sec^n x \) is not straightforward as there is no simple antiderivative for this function. However, using the reduction formula, we express this integral in terms of the integral of \( \sec^{n-2} x \), which is of a lower power. Each application of the reduction formula decreases the exponent by two, progressively simplifying the integral until it can be solved.
Importance in Integral Calculus
The importance of the reduction formula in integral calculus cannot be overstated. It not only enables the computation of complex integrals but also provides a systemic approach to solving problems. This formula demonstrates the recursive nature of integration, allowing successive iterations to break down a problem into more manageable parts. The reduction formula is also invaluable in solving indefinite integrals, where constants of integration are included, making it a versatile tool in a mathematician's arsenal.Integral Calculus
Integral calculus is a major branch of calculus that focuses on the concept of an antiderivative, which represents the area under a curve or, more generally, the accumulation of quantities. Essentially, while differential calculus deals with rates of change (derivatives), integral calculus deals with the total size or value (integrals).
In our exercise, we work on finding the integral of \( \sec^n x \), which is a form of antiderivative. Integration by parts is one method used within integral calculus to find the integral of products of functions. It is based on the product rule for differentiation and requires choosing parts of a function to systematically break down into simpler parts.
In our exercise, we work on finding the integral of \( \sec^n x \), which is a form of antiderivative. Integration by parts is one method used within integral calculus to find the integral of products of functions. It is based on the product rule for differentiation and requires choosing parts of a function to systematically break down into simpler parts.
Application and Techniques
There are various techniques in integral calculus which include, but are not limited to, substitution, partial fractions, and trigonometric identities. Each method has its own set of rules and suitable scenarios. For instance, the substitution method is often used when a function's derivative is present elsewhere in the integral. Integral calculus thus requires a strong foundation in algebraic manipulation and understanding of functions to effectively tackle a wide array of problems.Secant Integration
Secant integration refers to the integration of functions involving the secant (\( \sec x \)) trigonometric function. Since the secant function can be expressed as the reciprocal of the cosine function, or \( \sec x = \frac{1}{\cos x} \), integrals that involve secants can sometimes be challenging due to the behavior of the secant function, particularly its undefined values and asymptotes.
In the provided exercise, the integral \( \int \sec^n x dx \) involves raising the secant function to a power, making direct integration difficult. Reduction formulas and trigonometric identities become invaluable tools for simplifying these types of integrals. Remembering that \( \tan^2 x = \sec^2 x - 1 \) allows the expression to be rewritten in a more workable form, facilitating the integration by parts method.
In the provided exercise, the integral \( \int \sec^n x dx \) involves raising the secant function to a power, making direct integration difficult. Reduction formulas and trigonometric identities become invaluable tools for simplifying these types of integrals. Remembering that \( \tan^2 x = \sec^2 x - 1 \) allows the expression to be rewritten in a more workable form, facilitating the integration by parts method.