Chapter 5: Problem 44
Volume of a Torus } Repeat Exercise 43 for a torus formed by revolving the
region bounded by the circle \(x^{2}+y^{2}=r^{2}\) about the line \(x=R,\) where
\(r
Chapter 5: Problem 44
Volume of a Torus } Repeat Exercise 43 for a torus formed by revolving the
region bounded by the circle \(x^{2}+y^{2}=r^{2}\) about the line \(x=R,\) where
\(r
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Get started for freeState the definition of work done by a constant force.
The centroid of the plane region bounded by the graphs of \(y=f(x), y=0, x=0,\) and \(x=1\) is \(\left(\frac{5}{6}, \frac{5}{18}\right)\). Is it possible to find the centroid of each of the regions bounded by the graphs of the following sets of equations? If so, identify the centroid and explain your answer. (a) \(y=f(x)+2, y=2, x=0,\) and \(x=1\) (b) \(y=f(x-2), y=0, x=2,\) and \(x=3\) (c) \(y=-f(x), y=0, x=0,\) and \(x=1\) (d) \(y=f(x), y=0, x=-1,\) and \(x=1\)
If the portion of the line \(y=\frac{1}{2} x\) lying in the first quadrant is revolved about the \(x\) -axis, a cone is generated. Find the volume of the cone extending from \(x=0\) to \(x=6\).
(a) use a graphing utility to graph the region bounded by the graphs of the equations, (b) find the area of the region, and (c) use the integration capabilities of the graphing utility to verify your results. $$ f(x)=\frac{1}{x^{2}} e^{1 / x}, \quad y=0, \quad 1 \leq x \leq 3 $$
In Exercises \(1-4\), set up the definite integral that gives the area of the region. $$ \begin{array}{l} f(x)=x^{2}-6 x \\ g(x)=0 \end{array} $$
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