Question

Determine whether the statement is true or false. If it is false, explain why or give an example that shows it is false. If \(F(x)\) and \(G(x)\) are antiderivatives of \(f(x),\) then \(F(x)=G(x)+C\)

Short answer

The statement is true. If two functions are antiderivatives of the same function, they differ by a constant.

Step-by-step solution

Understanding the statement

Analyze the statement: If \(F(x)\) and \(G(x)\) are antiderivatives of \(f(x),\) then \(F(x)=G(x)+C\). This means, if two functions \(F(x)\) and \(G(x)\) are both antiderivatives of the same function \(f(x)\), then the difference between \(F(x)\) and \(G(x)\) should be some constant \(C\).

Verifying the statement

Consider the fundamental theorem of calculus, which states that if \(F\) is an antiderivative of \(f\) on an interval, then any other antiderivative \(G\) of \(f\) on that interval is \(F+C\), for some constant \(C\). This is in sync with the given statement in the problem.

Conclusion

Based on the fact from the fundamental theorem of calculus about antiderivatives, the statement given can be verified as true. Two functions, if they are both antiderivatives of a third function, will differ by a constant.

Key concepts

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus is a cornerstone in the field of calculus, crucial for understanding the relationship between differentiation and integration, two of the main concepts in the subject. This theorem bridges the gap between antiderivatives and definite integrals, asserting that differentiation and integration are, in a sense, inverse operations.

To grasp this concept, imagine you have a smooth curve on a graph that represents a function, say, \(f(x)\). If you were to find the area under this curve from a to b, you'd perform a definite integral of \(f(x)\). Now, the theorem states that in order to evaluate this integral, you can use an antiderivative (a function whose derivative is \(f(x)\)) of the function. Specifically, if \(F(x)\) is any antiderivative of \(f(x)\), then the definite integral of \(f(x)\) from a to b is given by \(F(b) - F(a)\).

The beauty of the Fundamental Theorem of Calculus lies in its simplicity and power, as it allows us to use antiderivatives to easily calculate areas and enables the computation of definite integrals through a process known as indefinite integration.

Constant of Integration

When we talk about antiderivatives in calculus, the constant of integration is a critical concept to understand. Upon finding an antiderivative, also called indefinite integral, of a function \(f(x)\), one must remember that there are actually infinitely many antiderivatives for \(f(x)\), since the process of taking derivatives wipes out any added constants.

For instance, if you were to take the derivative of \(F(x) = x^2 + 5\), you'd get \(f(x) = 2x\). However, if someone started with \(f(x) = 2x\) and looked for an antiderivative, they could find \(F(x) = x^2\), or \(F(x) = x^2 + 1\), or \(F(x) = x^2 - 3\), or any \(F(x) = x^2 + C\), where \(C\) represents any real number. That's the constant of integration, signifying that we need to account for all the possible vertical shifts (up or down) that are lost in the derivative process.

This is a pivotal understanding in calculus as it speaks to the broader idea of families of functions being related through differentiation and integration, rather than a single, unique function.

True or False Problems in Calculus

True or false problems in calculus are a great way to test understanding of complex concepts. They require a student not only to verify the validity of a statement, but also to grasp the underlying principles that make it true or false. These problems often touch on various aspects of calculus such as limits, derivatives, integrals, and theorems.

The exercise given earlier is an example: determining if two antiderivatives of the same function differ only by a constant. To approach this kind of true or false question, a methodical analysis is imperative. It's crucial to not just know the rules and theorems, like the Fundamental Theorem of Calculus, but also to understand why they are true. It's this depth of understanding that allows for the correct application of these rules and the unraveling of more complex problems in calculus.

For educators and content creators, it is important to design such exercises to not only assess the students' memorization of facts but also to encourage a deeper conceptual understanding. Scaffolded support, such as step-by-step solutions, can be incredibly helpful for students navigating these true or false terrains in their learning journey.