Question

Approximation In Exercises 57 and 58 , determine which value best approximates the area of the region between the \(x\) -axis and the graph of the function over the given interval. (Make your selection on the basis of a sketch of the region and not by performing calculations.) \(f(x)=4-x^{2}, \quad[0,2]\) (a) -2 (b) 6 (c) 10 (d) 3 (e) 8

Short answer

The value that best approximates the area of the region between the x -axis and the graph of the function over the given interval [0,2] is (b) 6.

Step-by-step solution

Graph the Function

Draw the graph of the function \(f(x)=4-x^{2}\) within the interval [0,2]. The graph will be a downward-opening parabola intersecting y-axis at point (0,4) and intersecting the x-axis at points (-2,0) and (2,0). However, as our interest is on positive x-values only, we focus on the interval from 0 to 2.

Identify The Area of Interest

The area of interest is the region enclosed between the x-axis (the horizontal line y = 0), the function \(f(x)=4-x^{2}\) and the vertical lines at x = 0 and x = 2. Looking at the graph we see a shape which looks like right-angled triangle and a semi-circle.

Visual Approximation of The Area

As the shape of the area is familiar, we can approximate it by considering pieces of simple shapes like triangle and semi-circle. The triangle would have base around 2 and height 4, and the semi-circle would have radius around 1. So considering the area of this combination would be far greater than the areas of individual simple shapes.

Compare with the Given Choices

Now compare your visual approximation of the area with the given choices (a) -2 (b) 6 (c) 10 (d) 3 (e) 8. It's important to note that the area cannot be a negative number as in choice (a), therefore this option can be immediately discarded. In comparing the remaining choices with our approximation, it can be seen that (b) 6 is the option that best matches our visual approximation.

Key concepts

Graph of a Function

Understanding the graph of a function is fundamental when studying calculus, especially when estimating the area under a curve visually. In the exercise, we're presented with the function f(x) = 4 - x^2, which graphs as a downward-opening parabola. This particular shape is symmetrical, crossing the x-axis at (2, 0) and (-2, 0), and peaking at the y-axis at (0, 4). This graph gives us a visual representation of how the function behaves across different values of x.

By observing the graph within the interval [0,2], we can identify specific characteristics which assist in the process of approximation. For instance, the area to be approximated is bounded by the curve, x-axis, and the vertical lines x = 0 and x = 2. The ability to correctly sketch and interpret the graph of a function is an invaluable skill that aids significantly in solving calculus problems.

Visual Approximation

Visual approximation is a technique that leverages our innate ability to recognize and estimate the size of familiar geometric shapes. When it comes to calculating areas in calculus, especially when we don't have access to the exact mathematical formulas, visual approximation can be quite useful. In our exercise, the area under the curve of f(x) resembles a combination of a triangle and a semi-circle.

Through estimating the area of these composite shapes, we get a tangible sense of the size of the region in question. Although this method does not yield a precise answer, it provides a reasonable estimate that can often guide us to the correct choice from a set of options. Using this approximation, we can conclude that the area must be greater than the area of the individual shapes, thus narrowing down the possible correct answer significantly.

Integral Calculus

Integral calculus is the branch of calculus that deals with finding the area under the graph of a function. It encompasses a range of techniques for evaluating the integral of a function, which represents the accumulation of quantities, such as areas. Although the exercise instructed to avoid calculations, in a more standard scenario, we would set up an integral to compute the exact area.

In our case, we would integrate f(x) from 0 to 2 to find the precise area. This mathematical process would involve finding the antiderivative of f(x) and evaluating it at the bounds of the interval. Integral calculus is a powerful tool for solving a variety of practical problems beyond area, including volume, work, and other physical quantities that accumulate over a range.

Area Under Curve

The concept of the area under the curve is a cornerstone of integral calculus. In our exercise, we refer to the space that lies below the function f(x) = 4 - x^2 and above the x-axis within the bounds of the interval [0,2]. This area corresponds to the integral of the function over the specified range.

Important to note is that the area between a curve and the x-axis takes into account both above and below portions relative to the axis. However, since areas are conventionally positive, when using integrals, the convention is to consider the net area - positive above the axis and negative below it. For the problem at hand, since we only deal with the curve above the x-axis, the estimated area must be positive, eliminating any negative options right away.