Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

(a) Sketch the region whose area is represented by \(\int_{0}^{1} \arcsin x d x\) (b) Use the integration capabilities of a graphing utility to approximate the area. (c) Find the exact area analytically.

Short Answer

Expert verified
By using the analytical solution, the exact area under the curve \(y = \arcsin x\), for \(x\) between 0 and 1, is found to be \(\frac{\pi}{4} - \frac{1}{2}\).

Step by step solution

01

Drawing of the graph

First, on a Cartesian plane, graph the function \(y = \arcsin x\) for \(x\) ranging from 0 to 1. The area under the curve of this function above the \(x\)-axis between these two \(x\)-values corresponds to the value of the integral \(\int_{0}^{1} \arcsin x dx\).
02

Approximate area calculation

Load the graph of the function \(y = \arcsin x\) onto a graphing calculator, and use its function to calculate numerical definite integrals. Set the upper and lower limits of integration to be 1 and 0 respectively to get the approximate value of the integral \(\int_{0}^{1} \arcsin x dx\), which is an estimation of the area under the curve.
03

Analytical Calculation

To determine the exact area, use integration methods. Since the integral of \(\arcsin x\) is \(x\arcsin x + \sqrt{1 - x^2}\), compute \(\int_{0}^{1} \arcsin x dx\) from these antiderivative and the limits of integration. At the end, the exact value obtained will be the exact area under the curve.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free